First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
They traveled 292 miles on day two.
Known: On the first day they traveled 365 and on the second they traveled 20% less.
Solution:
If they traveled 20% less on the second day, that means they traveled 80% of the distance they traveled the first day.
365 miles * .8 = 292.
You could also solve this as:
20% of 365 is 73 miles
365 * .2 = 73.
So they traveled 73 less miles on the second day.
365 miles on the first day - 73 miles less on the second day = 292 miles.
I hope this helps!
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So since her balance must be at least 500, her ballance cannot reach 500
so 794-500=294
see how many 25's you can fit into 294
we know that 4 25's =100 and 294 is roughly 300
so 4 times 3=12
we minus one of the 25's because 294 is less than 300 so
the innequality is
>means more than
794-25x>500
