Given f(x)=3x²-5x-2
a) To find f(a+h) replace x with a+h in the given function. So,
f(a+h)=3(a+h)²-5(a+h)-2
=3(a²+2ah+h²)-5(a+h)-2 By using the formula (x+y)²=x²+2xy+y².
=3a²+6ah+3h²-5a-5h-2 By distributing property.
b) Similarly to find f(a) we need to replace x with a. So,
f(a)=3a²-5a-2
So, f(a+h)-f(h)= (3a²+6ah+3h²-5a-5h-2)-(3a²-5a-2)
=3a²+6ah+3h²-5a-5h-2-3a²+5a+2.
=6ah+3h^2-5h (All other terms has been cancel out)
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS≅RS | Reflexive Property
3.) △RST ≅ △RSQ | AAS Triangle Congruence Property
Answer:
10 quarters = $2.50
10 nickels = $0.50
that leaves $0.20 for other coins (dimes / pennies)
Step-by-step explanation:
First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.
Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.
This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.
Answer:
3
Step-by-step explanation:
The sum of 165 and 633 will be
165+633=798
When the sum is reduced to 266, it means the sum is reduced by 798/266=3
The sum is reduced three times.
Therefore, as per the question, this sum was reduced three different times
