Answer:
(6,2)
Step-by-step explanation:
Variable Definitions:
x= the number of commercials
y= the number of movies
Each commercial earns Emily $50, so x commercials would earn her 50x dollars in royalties. Each movie earns Emily $150, so y movies would earn her 150y dollars in royalties. Therefore, the total royalties 50x+150y equals $600:
50x+150y=600
Since Emily's songs were played on 3 times as many commercials as movies, if we multiply 3 by the number of movies, we will get the number of commercials, meaning x equals 3y.
x=3y
Write System of Equations:
50x+150y=600
x=3y
Solve for y in each equation:
1) 50x+150y=600
150y=−50x+600
y=-1/3x+4
2) x=3y
y=1/3x
The x variable represents the number of commercials and the yy variable represents the number of movies. Since the lines intersect at the point (6,2) we can say:
Emily's songs were played on 6 commercials and 2 movies.
The answer to this question would be:
<span>The function f(x) = 9,000(0.95)x represents the situation.
After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
</span>
In this problem, there are 9,000 bees and the amount is decreased 5% each year. Decreased 5% would be same as become (100%-5%=)95% each year. Then the function should be like:
f(x)= 9,000 * 95%^ x= 9,000 * 0.95^x
If you put X=2 and X=4 the result would be:
<span>f(2) = 9,000* (0.95)^2= 8122.5 (round up to tenth will be 8120)
</span>f(4) = 9,000* (0.95)^4= 7330.5
Answer:
Step-by-step explanation:
The best option is for the consultant to remove these data points because they are outliers. Unusual data points which are located far from rest of the data points are known as outliers.
Answer:
a.) C(q) = -(1/4)*q^3 + 3q^2 - 12q + OH b.) $170
Step-by-step explanation:
(a) Marginal cost is defined as the decrease or increase in total production cost if output is increased by one more unit. Mathematically:
Marginal cost (MC) = change in total cost/change in quantity
Therefore, to derive the equation for total production cost, we need to integrate the equation of marginal cost with respect to quantity. Thus:
Total cost (C) = Integral [3(q-4)^2] dq = -(1/4)*(q-4)^3 + k
where k is a constant.
The overhead (OH) = C(0) = -(1/4)*(0-4)^3 + k = -16 + k
C(q) = -(1/4)*(q^3 - 12q^2 + 48q - 64) + k = -(1/4)*q^3 + 3q^2 - 12q -16 + k
Thus:
C(q) = -(1/4)*q^3 + 3q^2 - 12q + OH
(b) C(14) = -(1/4)*14^3 + 3*14^2 - 12*14 + 436 = -686 + 588 - 168 + 436 = $170
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