Kevin has a spinner that has 10 equal sections and 2 sections of each color—red, blue, green, yellow, and purple. Kevin spins th
e spinner 180 times. Kevin determines about how many times the spinner will land on red or green, and his work is shown below.
What mistake did Kevin make, if any?
Kevin has the formula reversed; it should be the total number of sections over the number of red or green sections.
Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.
Kevin should multiply by the number of sections in the spinner rather than the total number of spins.
Kevin calculated the prediction correctly and did not make any mistakes.
What mistake did Kevin make, if any?
Kevin has the formula reversed; it should be the total number of sections over the number of red or green sections.
Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.
Kevin should multiply by the number of sections in the spinner rather than the total number of spins.
Kevin calculated the prediction correctly and did not make any mistakes.
2 answers:
<h2>Answer:</h2>
The mistake that kevin make is:
- Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.
It was given that there are 10 sections in the spinners 2 of each color.
Hence, in order to find the probability that the spinner lands on green or red is:
He need to find the total sections which are red or green,.
There are 4 sections which are red or green
( Since 2 are green and 2 are red)
and the probability that it will land on green or red is:
Hence, she should have taken 4 in the numerator to calculate the probability.
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer