Kevin has a spinner that has 10 equal sections and 2 sections of each color—red, blue, green, yellow, and purple. Kevin spins th
e spinner 180 times. Kevin determines about how many times the spinner will land on red or green, and his work is shown below.
What mistake did Kevin make, if any?
Kevin has the formula reversed; it should be the total number of sections over the number of red or green sections.
Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.
Kevin should multiply by the number of sections in the spinner rather than the total number of spins.
Kevin calculated the prediction correctly and did not make any mistakes.
What mistake did Kevin make, if any?
Kevin has the formula reversed; it should be the total number of sections over the number of red or green sections.
Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.
Kevin should multiply by the number of sections in the spinner rather than the total number of spins.
Kevin calculated the prediction correctly and did not make any mistakes.
2 answers:
<h2>Answer:</h2>
The mistake that kevin make is:
- Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.
It was given that there are 10 sections in the spinners 2 of each color.
Hence, in order to find the probability that the spinner lands on green or red is:
He need to find the total sections which are red or green,.
There are 4 sections which are red or green
( Since 2 are green and 2 are red)
and the probability that it will land on green or red is:
Hence, she should have taken 4 in the numerator to calculate the probability.
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Answer:
<u>Properties that are present are </u>
Property I
Property IV
Step-by-step explanation:
The function given is where b > 1
Let's take a function, for example,
Let's check the conditions:
I. As the x-values increase, the y-values increase.
Let's put some values:
y = 2 ^ 1
y = 2
and
y = 2 ^ 2
y = 4
So this is TRUE.
II. The point (1,0) exists in the table.
Let's put 1 into x and see if it gives us 0
y = 2 ^ 1
y = 2
So this is FALSE.
III. As the x-value increase, the y-value decrease.
We have already seen that as x increase, y also increase in part I.
So this is FALSE.
IV. as the x value decrease the y values decrease approaching a singular value.
THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.
This is TRUE.
Option I and Option IV are true.