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ololo11 [35]
2 years ago
10

A hibernating animal lost 5 pounds. Write a signed number to represent this weight change.

Mathematics
1 answer:
vampirchik [111]2 years ago
8 0

Answer:

-2

Step-by-step explanation:

The sign would be negative because the pounds were lost not gained

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Julian is using a biking app that compares his position to a simulated biker traveling Julian's target speed. When Julian is beh
Gwar [14]

Answer:

11 km/hr.

Step-by-step explanation:

Given information:

Simulated speed = 20/km/h

Time = 15 mins = 1/4 hr = 0.25 hr

Distance Covered as per simulated speed = 20\times \frac{1}{4}=5km

Position of Julian according to the app = -2\frac{1}{4}=-2.25.

Actual distance covered by the bike is

Distance= 5 - 2.25 = 2.75km

Formula for speed:

\text{Average Speed}=\frac{Distance}{Time}

\text{Average Speed}=\frac{2.75}{0.25}

\text{Average Speed}=11

Therefore, the average speed of Julian is 11 km/hr.

5 0
2 years ago
What is the length of the y-component of the vector plotted below?
Inessa05 [86]

Answer:

Option A.

Step-by-step explanation:

The vector shown in the figure has components on the x axis and on the y axis.

If each small box on the draw represents a unit, it can be seen that the vector has a component of<u> length equal to 1 on the positive y-axis </u>and a length equal to 4 on the positive x-axis.

Look at the attached image

The sum of these two components results in the vector shown in the figure. Therefore the correct option is option A.

The length is equal to 1


7 0
2 years ago
If one serving is 1/6 of a tray of lasagna, how many servings are in three trays of lasagna?
lbvjy [14]

Answer:

18 servings

Step-by-step explanation:

\dfrac{3}{(\frac{1}{6})}= \\\\3\times \left(\frac{6}{1}\right)= \\\\3\times 6= \\\\18

Hope this helps!

4 0
2 years ago
a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?
Nastasia [14]
W^2=80
W SQRT80
W=8.94 ANS.FOR THE WIDTH
L=3*8.94=26.83 ANS.FOR THE LENGTH
PROOF:
240=8.94*26.83
240=240

3 0
2 years ago
A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. determ
Temka [501]
The confidence interval would be (0.122, 0.278).

We first find our z-score.  We want a 95% confidence interval:

0.95/2 = 0.475

Looking this up in the z-table, (http://www.statisticshowto.com/tables/z-table/) we see the z-score is 1.96.

The formula we will use is:

p \pm z\sqrt{\frac{p(1-p)}{n}}

In this problem, p = 20/100 = 0.2, and n=100:

0.2 \pm 1.96\sqrt{\frac{(0.2)(0.8)}{100}}&#10;\\&#10;\\0.2\pm 0.0784&#10;\\&#10;\\(0.2-0.0784, 0.2+0.0784)&#10;\\&#10;\\(0.1216,0.2784)
8 0
2 years ago
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