Given data, cos(A - B) = cosAcosB + sinAsinB
<span>let, A=60' and B=30' ( here the ' sign bears degree) </span>
<span>L.H.S = cos(A - B) </span>
<span>=cos (60'-30) ( using value of A and B ) </span>
<span>=cos30' </span>
<span>= sqrt3/2 </span>
<span>R.H.S= cosAcosB + sinAsinB </span>
<span>=cos60' cos30' + sin60' sin30' </span>
<span>= 1/2* sqrt3/2+ sqrt3/2*1/2 </span>
<span>= sqrt3/4 + sqrt3/4 </span>
<span>=2 sqrt3/4 </span>
<span>= sqrt3/2 </span>
<span>so L.H.S =R.H.S or cos(A - B) = cosAcosB + sinAsinB</span>
Remark
The entire trip costs 485 dollars. She has a hundred, and you are looking for the number of weeks needed to save for the trip.
Step one
Set up the basic equation.
35w + 100 ≥ 485
Step two
solve
35w + 100 ≥ 485 Subtract 100 from both sides.
35W ≥ 485 - 100
35W ≥ 385 Divide by 35
W ≥ 385 / 35
W ≥ 11 weeks.
Since we don't have choices, we can't eliminate those that are wrong.
If I had to guess I would say it was something that looked like
35W + 100 ≥ 485
Answer:
A. $3992.50
Step-by-step explanation:
Credit line - $8,000.00
Summary
- Previous Balance Payments - $2,500.00
- Credits - $1,500.00
- New Purchases - $3,000.00
- Finance Charge - $7.50
- New Balance - $4,007.50
Available credit= credit line - new balance = $8000 - $4007.50= $3992.50
Answer:
8 hours
Step-by-step explanation:
$1,300/$32.50 = 40
$1,040/$32.50 = 32
40-32=8
