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1 year ago

11

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?

2 answers:

FrozenT [24]1 year ago

7 0

Quadratic equation: ax² + bx + c =0

x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a

6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6

x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31

sergejj [24]1 year ago

7 0

Answer: A

Step-by-step explanation:

The answer is A on Edge 2020

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Bob spent $64 for two shirts, including tax. The difference between the costs of the shirts was $16. Write two equations that yo

djyliett [7]

x+y=64 and x-y=16 can be used to solve the system.

Step-by-step explanation:

Let,

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Which statements are true about the rules of division? Check all that apply.

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In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the

Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

$(AB)^2=(BC)^2+(AC)^2$

$(13)^2=(BC)^2+(5)^2$

$169=(BC)^2+25$

$BC=12$

$\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin A=\frac{BC}{AB}$

$A=\sin ^{-1}\frac{12}{13}$

$A=67.38$

Bisector divides the angle in two equal parts, therefore,

$A'=\frac{67.38}{2} =33.69$

In triangle ACD.

$\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}$

$\cos A'=\frac{AC}{AD}$

$\cos (33.69^{\circ})=\frac{5}{AD}$

$0.832=\frac{5}{AD}$

$AD=\frac{5}{0.832} =6.009\approx 6.01$

Therefore the length of the angle bisector of angle ∠A is 6.01.

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1 year ago

A cylinder has a radius of 1.6 meters. Its volume is 95 cubic meters. Find it's height to the nearest tenth of a meter.

docker41 [41]

<h2>The height of cylinder is 11.8 meters</h2>

<em><u>Solution: </u></em>

<em><u> The volume of cylinder is given as:</u></em>

$V = \pi r^2h$

Where,

r is the radius and h is the height of cylinder

From given,

V = 95 cubic meters

r = 1.6 meters

h = ?

<em><u> Substituting the values we get,</u></em>

$95 = 3.14 \times 1.6^2 \times h\\\\95 = 8.0384 \times h\\\\h = \frac{95}{8.0384}\\\\h = 11.818 \approx 11.8$

Thus height of cylinder is 11.8 meters

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1 year ago