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2 years ago

The figure shows rhombus ABCD. Which of the following conditions satisfies the criteria for rhombi?

Mathematics

2 answers:

Vitek1552 [10]2 years ago

8 0

Answer:

BEC is 90 degrees

Step-by-step explanation:

MA_775_DIABLO [31]2 years ago

3 0

Answer:90

Step-by-step explanation:

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On a coordinate plane, a parabola opens up. It starts in quadrant 1, crosses the x axis where the vertex is in quadrant 4, and c

andrew-mc [135]

F(x) = (x - 8)2-6

if you simplify the equation you’re left with f(x) = (x - 8) - 4. there are two transformations that can be derived from this equation: translate horizontally right 8 and translate vertically down 4. because the parabola starts in quadrant 1, the parabola needs to be translated right opposed to left to match this. since the parabola’s vertex is in the negative quadrant 4, the function needs to be moved down which matches the second vertical translation the equation gives us.

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The average cost of gas where you live is $3.50 per gallon, you are trying to decide whether to buy a hybrid or standard car. Th

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Answer:

Step-by-step explanation:

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For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0

2 years ago

From past experience, a company has found that in carton of transistors: 92% contain no defective transistors 3% contain one def

jasenka [17]

Answer:

$E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500$

In order to find the variance we need to find first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300$

The variance is calculated with this formula:

$Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075$

And the standard deviation is just the square root of the variance and we got:

$Sd(X) = \sqrt{0.3075}= 0.5545$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X

X 0 1 2 3

P(X) 0.92 0.03 0.03 0.02

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500$

In order to find the variance we need to find first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300$

The variance is calculated with this formula:

$Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075$

And the standard deviation is just the square root of the variance and we got:

$Sd(X) = \sqrt{0.3075}= 0.5545$

8 0

2 years ago

Ratnam hired a car from a car renting agency which charges a flat amount of Rs x for travelling up to 40 kilometres and Rs. y pe

QveST [7]

Answer:

Rs. X + Rs. 10y

Step-by-step explanation:

Charge for 40 km travel = Rs. x per km

Charge for every additional km traveled = Rs. y

Amount paid for 50 km

Fixed charge for 40km = Rs. X

Additional km = 50 - 40 = 10 kilometer

Total charge :

Rs. X + Rs. 10y

7 0

1 year ago