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Semenov [28]
2 years ago
5

ANSWER QUICKLYYY PLEASEE

Mathematics
1 answer:
stira [4]2 years ago
3 0

Answer:

C

Step-by-step explanation:

6a^2 is the formula

plug in and solve

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there are two pizzas. conor ate 1⁄4 of a pizza, brandon 2⁄8, tyler 3⁄4, and audrey 4⁄8. who ate the most of the two pizzas? a. a
Sindrei [870]
The best way to determine which among the fractions has the greatest value, convert all of them to their decimal equivalents. To do so, divide the numerator by the denominator. Conor ate 0.25 of the pizza, Brandon also 0.25, Tyler 0.75, and Audrey 0.5. Thus, the answer is letter "B. Tyler".
7 0
2 years ago
Read 2 more answers
A scientist had a bottle that contains 56.6 ML of a solution. she used 3.2 ML of the solution for an experiment then she poured
hjlf
1. 56.6 - 3.2 = 53.4
2. 53.4 divided by 2 = 26.7
3. 26.7 - 6 = 20.7
Answer: 20.7 mL
3 0
2 years ago
At a bake shop, the cost of flour is $2.50 per pound and increases at a rate of $0.07 per month. The cost of cocoa is $6.00 per
Vesna [10]

Answer:

Step-by-step explanation:

We will find two equations for this system, one representing flour and the other representing cocoa.  For the flour, we start with $2.50, and the cost goes up .07 per month, x. The equation for that is

y = .07x + 2.50

For the cocoa, the equation is written in the exact same way, but the cost goes down.  Down is a negative thing while up is a positive thing.  The cost starts at $6.00 and goes down .03 per month, x. The equation for that is

y = -.03x + 6.00

Comparing the first equation to the second, the .07 is positive because the cost goes UP that amount per month and the .03 is negative because the cost goes DOWN that amount per month.  Get it?

If y is cost and we are tryong to find out where the cost is the same, we are looking for when y is the same.  If the first y is equal to .07x + 2.50 and the second y is equal to -.03x + 6.00, and y is equal to y, then

.07x + 2.50 = -.03x + 6.00 (this is setting the first y equal to the second y).  This is the system that describes how to find the number of months x when the cost y is the same. We'll solve it just for practice.

Combining like terms we get

.10x = 3.5 so

x = 35

Now back sub in what x equals to solve for y.  If x = 35, then in the first equation,

.07(35) + 2.50 = y and

y = 4.95 (you could have used the second equation and subbed in 35 for x and you will get the exact same y value.  Promise!)

What this answer tells us is that 35 months after the start of this pricing, the cost of flour will be the same as the cost of cocoa.  But immediately after 35 months, the costs will not be the same anymore.  It is only AT 35 months.  At 36 months, the costs will be different.

7 0
2 years ago
Webassign find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (6, 36), an
Dvinal [7]
First find the tangent line

dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36

alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2

so we do \int\limits^6_0 {x^2} \, dx - \int\limits^6_0 {12x-36} \, dx = \int\limits^6_0 {x^2-(12x-36)} \, dx = \int\limits^6_0 {x^2-12x+36} \, dx =
[\frac{x^3}{3}-6x^2+36x]\limits^6_0=(\frac{6^3}{3}-6(6)^2+36(6))-(0)=\frac{216}{3}-216+216= 72+0=72

the area under the curve bounded by the lines and the x axis is 72 square units
4 0
2 years ago
Each airline passenger and his or her luggage must be checked to determine whether he or she is carrying weapons on to the airpl
Dafna1 [17]

Answer:

a

P_k  = 0.83

b

 N_{\mu} \approx  4 \ passengers

c

T_{\lambda} =  0.5 \ minutes

Step-by-step explanation:

From the question we are told that

The average number of passengers that arrive per minute is \lambda = 10

The average number of check that can be carried out in one minute is \mu= 12

Generally the probability that a passenger will have to wait before being checked for weapons is mathematically represented as

        P_k  = \frac{\lambda }{ \mu }

=>    P_k  = \frac{10 }{ 12}

=>    P_k  = 0.83

Generally the number of passengers are waiting in line to enter the checkpoint is mathematically represented as

     N_{\mu} =  \frac{\lambda^2}{\mu (\mu -\lambda) }

=>  N_{\mu} =  \frac{10^2}{12 (12 -10) }

=>  N_{\mu} \approx  4 \ passengers

Generally the average time a passenger spend at the checkpoint is mathematically represented as

      T_{\lambda} = \frac{ \frac{\lambda}{(\mu - \lambda)} }{ \lambda}

=>   T_{\lambda} = \frac{ \frac{ 10}{(12 - 10)} }{10}

=>   T_{\lambda} =  0.5 \ minutes

5 0
1 year ago
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