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Murrr4er [49]
1 year ago
11

Suppose S is a recursively defined set, defined by the number 1 is in S if n is in S, then so is 3n+2 - if n is in S, then so is

5n-1 if n is in S, then so is n+7 Suppose you want to prove using structural induction that all members of S have a certain property. What do you have to prove in the base step? That the numbers 5,4 and 8 have the property. That the number 1 has the property, and the numbers 5, 4 and 8. O That the numbers 5, 4 and 8 are in the set S. That the number 1 has this property.
Mathematics
1 answer:
jolli1 [7]1 year ago
8 0

Answer:

That the number 1 has this property.

Step-by-step explanation:

For base step we have to prove that number 1 has the property.

so therefore the smallest number of S is 1.

So that the number 1 has this property.

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