I hope the equation will be 2000=16000(1-r)^t because t is missing in the equation which we need to find.
Given rate: r= 35%= 0.35.
So, first step is to plug in 0.35 for r in the given formula to get the value of t.
Hence, the equation will be:
2000=16000(1-0.35)^t
2000=16000(0.65)^t (By subtraction)
2000/16000= 16000(0.65)^t /16000 (Dividing each sides by 16000)
0.125 = 0.65^t (By simplifying).
log 0.125 = log 0.65^t (Taking log each sides to isolate t).
log 0.125 = t log 0.65 (By applying the log property).
(Dividing each sides by log 0.65)
-0.903/-0.187 =t
t= 4.83
t= 5 ( Rounded to nearest integers)
So, Devon's car is 5 years old.
Answer:
24 and 21
Step-by-step explanation:
the ratio of their ages is 8 : 7 = 8x : 7x ( x is a multiplier )
In 6 years
8x + 6 : 7x + 6 = 10 : 9
Express the ratio in fractional form
=
( cross- multiply )
9(8x + 6) = 10(7x + 6) ← distribute parenthesis on both sides
72x + 54 = 70x + 60 ( subtract 70x from both sides )
2x + 54 = 60 ( subtract 54 from both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Thus
Tony = 8x = 8 × 3 = 24
Vihaan = 7x = 7 × 3 = 21
Answer and Step-by-step explanation:
The computation of the class width for a frequency is shown below:
Class width is

= 10.86
= 11
Now the class limits for a frequency table
Particulars Lower class limit to upper class limit
First class 20 - 30
Second class 31 - 41
Third class 42 - 52
Fourth class 53 - 63
Fifth class 64 74
Six class 75 - 85
Seventh class 86 - 96