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2 years ago

A data set with whole numbers has a low value of 20 and a high value of 96.

Mathematics

1 answer:

Naya [18.7K]2 years ago

8 0

Answer and Step-by-step explanation:

The computation of the class width for a frequency is shown below:

Class width is

$= \frac{Range}{Number\ of\ class} \\\\ = \frac{96 - 20}{7}$

= 10.86

= 11

Now the class limits for a frequency table

Particulars Lower class limit to upper class limit

First class 20 - 30

Second class 31 - 41

Third class 42 - 52

Fourth class 53 - 63

Fifth class 64 74

Six class 75 - 85

Seventh class 86 - 96

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An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)

erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

18-20 Not 18-20 Total

Male 0.23 0.35 0.58

Female 0.16 0.26 0.42

Total 0.39 0.61 1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) = 0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0

2 years ago

In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t

AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

P(X = r) = $\binom{n}{r}p^{r}(1-p)^{n-r}$ for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

r = no. of success which is at least 5 in our case

p = probability of success which is probability of Roman Catholic of

0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= $\binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}$

= 56 * $0.9^{5} * (0.1)^{3}$ + 28 * $0.9^{6} * (0.1)^{2}$ + 8 * $0.9^{7} * (0.1)^{1}$ + 1 * $0.9^{8}$

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0

2 years ago

Susan is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices. Com

hoa [83]

Idk if this is correct but ugh ill try my best

B = 55 + .6x

65 = 55 + .6x

subtract 55 from each side

10 = .6x

Multiply each side by .6 =

6 = x or in this case m

A charges les than B when m > 6

tell me if I'm wrong if I am

4 0

2 years ago

Three erasers and five pencils cost $7.55. 6 erasers and 12 pencils cost $17.40. How much does 1 eraser cost? How much does 1 pe

Sphinxa [80]

Answer:

Step-by-step explanation:

erasers=e

pencils=p

3e+5p=7.55 ...(1)

6e+12p=17.40

divide by 2

3e+6p=8.70 ...(2)

(2)-(1) gives

p=8.70-7.55=1.15

from (1)

3e+5(1.15)=7.55

3e+5.75=7.55

3e=7.55-5.75

3e=1.80

e=1.80/3=0.60

cost of 1 eraser=$0.60

cost of 1 pencil =$1.15

7 0

2 years ago

Whitney bought a watch for $107.50. The finance charge was $11 and she paid for it over 6 months.

Anna11 [10]

Answer:

Her proximate APR is 5.1%

Step-by-step explanation:

The formula of the APR is $APR=\frac{FC}{A}$ × $\frac{m}{12}$ × 100%, where

FC is the finance charge
A is the amount financed
m is the number of months

∵ Whitney bought a watch for $107.5

∴ A = 107.5

∵ The finance charge was $11

∴ FC = 11

∵ She paid for it over 6 months

∴ m = 6

- Substitute these values in the formula above

∵ $APR=\frac{11}{107.5}$ × $\frac{6}{12}$ × 100%

∴ APR = 5.11627907%

- Round it to the nearest tenth

∴ APR = 5.1%

Her proximate APR is 5.1%

4 0

2 years ago