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denpristay [2]
2 years ago
15

A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o

f the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
Mathematics
1 answer:
yan [13]2 years ago
5 0
<span>The probability of missing the first shot is 40%. When she misses the first shot, the probability of missing the second shot is very, very low, only 5%. That means that the probability of missing both shots must be much smaller than the probability of missing the first shot.
 
40/100 * 5/100
0.4 * 0.05
= 0.02
= 2%</span>
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Emily an her dad share the cost of the meal in the ratio 2:3 emily’s Dad pays £52.20 what is the total cost of the meal
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£87.00

Emily's dad pays 3 parts of the meal

Divide £52.20 by 3 to find one part of the ratio

\frac{52.20}{3} = £17.40 ← 1 part of the ratio

2 parts = 2 × £17.40 = £34.80 ← Emily's share

total cost = £52.20 + £34.80 = £87.00


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2 years ago
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Suppose 1000 people enter a chess tournament. Use a rooted tree model of the tournament to determine how many games must be play
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Answer: 999 games

Step-by-step explanation:

There are many ways to illustrate the rooted tree model to calculate the number of games that must be played until only one player is left who has not lost.

We could go about this manually. Though this would be somewhat tedious, I have done it and attached it to this answer. Note that when the number of players is odd, an extra game has to be played to ensure that all entrants at that round of the tournament have played at least one game at that round. Note that there is no limit on the number of games a player can play; the only condition is that a player is eliminated once the player loses.

The sum of the figures in the third column is 999.

We could also use the formula for rooted trees to calculate the number of games that would be played.

i=\frac{l - 1}{m - 1}

where i is the number of "internal nodes," which represents the number of games played for an "<em>m</em>-ary" tree, which is the number of players involved in each game and l is known as "the number of leaves," in this case, the number of players.

The number of players is 1000 and each game involves 2 players. Therefore, the number of games played, i, is given by

i=\frac{l - 1}{m - 1} = i=\frac{1000 - 1}{2 - 1} = \frac{999}{1} =999

7 0
2 years ago
Triangles R S T and V U T are connected at point T. Angles R S T and V U T are right angles. The length of side R S is 12 and th
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Answer:

StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U

Step-by-step explanation:

The expression below means RS/VU = ST/UT

See the attachment for better explanation.

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2 years ago
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In a study conducted in the United Kingdom about sleeping positions, 1000 adults in the UK were asked their starting position wh
Strike441 [17]

Answer:

The 95% confidence interval would be given by (0.380;0.441)

Step-by-step explanation:

In a study conducted in the United Kingdom about sleeping positions, 1000 adults in the UK were asked their starting position when they fall asleep at night. The most common answer was the fetal position (on the side, with legs pulled up), with 41% of the participants saying they start in this position. Use a normal distribution to find and interpret a 95% confidence interval for the proportion of all UK adults who start sleep in this position. Use the fact that the standard error of the estimate is 0.016

1) Notation and definitions

X number of people who answer fetal position

n=1000 random sample taken

\hat p=0.41 estimated proportion of people who answer fetal position

p true population proportion of people who answer fetal position

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Confidence interval

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.41 - 1.96\sqrt{\frac{0.41(1-0.41)}{1000}}=0.380

0.41 + 1.96\sqrt{\frac{0.41(1-0.41)}{1000}}=0.441

The 95% confidence interval would be given by (0.380;0.441)

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