Notice that form 3 pm to 6:30 pm 3.5 hours have passed.
Since the function

represent the average number of cars that pass through an intersection x hours after 3:00 p.m, we are going to replace

with 3.5 to find <span>the average number of cars that pass through the intersection at 6:30 p.m
</span>





We can conclude that the <span>average number of cars that pass through an intersection at 6:30 pm is approximately 117. </span>
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Answer:
The figures are congruent because a 270° rotation about the origin and then a reflection over the x-axis will map ΔABC onto ΔLMN.
Two equations will not have solution if they are parallel and have different y-intercepts. Parallel lines have the same slope. In a slope-intercept form, the equation of the line can be expressed as,
y = mx + b
where m is slope and b is the y-intercept.
Given: 3x - 4y = 2
Slope-intercept: y = 3x/4 - 1/2
A. 2y = 1.5x - 2
Slope-intercept: y = 3x/4 - 1
B. 2y = 1.5x - 1
Slope-intercept: y = 3x/4 - 1/2
C. 3x + 4y = 2
Slope-intercept: y = -3x/4 + 1/2
D. -4y + 3x = -2
Slope-intercept: y = 3x/4 + 1/2
Hence, the answers to this item are A and D.
Answer:
coffee is the best answer in my mind