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alexira [117]
2 years ago
8

Two race cars are speeding around the racetrack at different speeds. One goes around the track in 2 minutes; the other goes arou

nd the track in 11/2 minutes. How often does the faster car pass the slower car?
Mathematics
2 answers:
PSYCHO15rus [73]2 years ago
6 0

one car takes 2 minutes for once around
so in 1 minute it does a 1/2 around
 .
second car takes 1 1/2 minutes for once around ( 1 1/2 = 3/2)
so in 1 minute it does 2/3 round 


 every minute the second car gains 2/3 -1/2 of the round

2/3 = 4/6, 1/2 = 3/6

4/6 - 3/6 = 1/6 of the track per minute


so every 6 minutes the faster car overtakes the slower car.

butalik [34]2 years ago
4 0

Answer:

6 minutes is the answer.

Step-by-step explanation:

One goes around the track in 2 minutes.

The other goes around the track in 1\frac{1}{2} or 1.5 minutes

WE will find the least common multiple of 2 and 1.5.

The LCM of 2 and 1.5 is 6.

That means in every 6 minutes, both the cars are at the same point.

We have to tell how often does the faster car pass the slower car. The answer is in 6 minutes.

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Mars2501 [29]
Notice that form 3 pm to 6:30 pm 3.5 hours have passed.
Since the function y=-6 x^{2} +51.5x+10.2 represent the average number of cars that pass through an intersection x hours after 3:00 p.m, we are going to replace x with 3.5 to find <span>the average number of cars that pass through the intersection at 6:30 p.m
</span>y=-6 x^{2} +51.5x+10.2
y=-6 (3.5)^{2} +51.5(3.5)+10.2
y=-6(12.25)+180.25+10.2
y=-73.5+190.45
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We can conclude that the <span>average number of cars that pass through an intersection at 6:30 pm is approximately 117. </span>
8 0
1 year ago
Read 2 more answers
A pet store contains 35 light green parakeets (14 females and 21 males) and 44 sky blue parakeets (28 females and 16 males). You
Mamont248 [21]
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB) 

Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)

Req:
- the probability that it is a female (F) or a sky blue (SB)

Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB) 
                 = [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
                 = 53.16 + 55.70 - 35.44
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You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%


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2 years ago
On a coordinate plane, 2 triangles are shown. Triangle A B C has points (negative 1, 1), (negative 4, 1) and (negative 1, 5). Tr
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Answer:

The figures are congruent because a 270° rotation about the origin and then a reflection over the x-axis will map ΔABC onto ΔLMN.

8 0
1 year ago
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Determine which equations below, when combined with the equation 3x-4y=2, will form a system with no solutions. Choose all that
svetoff [14.1K]
Two equations will not have solution if they are parallel and have different y-intercepts. Parallel lines have the same slope. In a slope-intercept form, the equation of the line can be expressed as,       
 
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where m is slope and b is the y-intercept.

Given: 3x - 4y = 2
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A. 2y = 1.5x - 2
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D. -4y + 3x = -2
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crimeas [40]

Answer:

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