Chris and Ben walked home from school. The distance Chris walked,in miles, is represented by point C on the number line. Ben wal
1 answer:
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Answer:
A.) Acceleration = 4.6 m/s^2
B.) Average speed = 47 m/s
Step-by-step explanation:
A.) From the graph, at t = 10s,
Velocity V = 46 m/s
Acceleration a = (change in V)/ time t
a = (46 - 0)/10
a = 46/10 = 4.6 m/s^2
B.) If we estimate the speed at 5 seconds intervals, then we have
Average speed = (36 + 46 + 49 + 50 + 50 +50 + 50) ÷ 7
Average speed = 331/7 = 47.29 m/s
Average speed = 47 m/s
