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Lilit [14]
2 years ago
11

If the median of the score distribution on this pop quiz is more than 170, the teacher will drop the next pop quiz. The pop quiz

scores followed this distribution: {180, 175, 163, 186, 153, 194, 198, 183, 187, 174, 177, 196, 162, 185, 174, 195, 164, 152, 144, 138, 125, 110}. What is the median of the distribution?
Mathematics
2 answers:
xxTIMURxx [149]2 years ago
8 0

Answer:

174.5

Step-by-step explanation:

MAVERICK [17]2 years ago
4 0
The median of a set of data is obtained by arranging the data from lowest to highest. In this pop quiz scores, the arrangements is as follows:

110, 125, 138, 144, 152, 153, 162, 163, 164, 174, 174, 175, 177, 180, 183, 185, 186, 187, 194, 195, 196, 198. 

There are 22 items in the list and the median is located in the middle position. In this case, it is the average of 174 (11th) and 175 (12th). Thus, the median is 174.5. 
You might be interested in
A stadium has two sponsorship deals. Deal A had revenue of $100,000 and expense of $10,000. Deal B has revenue of $50,000 and ex
horsena [70]

Answer:

Deal A) 90% Profit ; Deal B) 60% Profit

Step-by-step explanation:

Multiple ways of solving this problem here is one way:

100k-10k = 90k(Revenue) : Then you make this as a percent by 100k then multiply it by 100.

100*((100,000-10,000)/100,000) = 90%

The same is true for the other equation:

100*((50,000-20,000)/50,000) = 60%


4 0
1 year ago
Read 2 more answers
A recent survey shows that the probability of a college student drinking alcohol is 0.6. further, given that the student is over
Murrr4er [49]

Answer:

0.24

Step-by-step explanation:

These events are not mutually exclusive; this means they can happen at the same time.

For two events A and B that are not mutually exclusive,

P(A and B) = P(A) * P(B|A)

Let A be the event "over 21 years old" and B be the event "drinks alcohol".  

The probability that a student is over 21 years old is 0.3; this is because 30% of the students are over 21 years old.

The probability that a student drinks alcohol given they are over 21 is 0.8.

This gives us

P(A and B) = 0.3(0.8) = 0.24

8 0
2 years ago
Read 2 more answers
Gianna is going to throw a ball from the top floor of her middle school. When she throws the ball from 32feet above the ground,
Jlenok [28]

Answer:

There are two times for the ball to reach a height of 64 feet:

1 second after thrown ⇒ the ball moves upward

2 seconds after thrown ⇒ the ball moves downward

Step-by-step explanation:

* Lets explain the function to solve the problem

- h(t) models the height of the ball above the ground as a function

 of the time t

- h(t) = -16t² + 48t + 32

- Where h(t) is the height of the ball from the ground after t seconds

- The ball is thrown upward with initial velocity 48 feet/second

- The ball is thrown from height 32 feet above the ground

- The acceleration of the gravity is -32 feet/sec²

- To find the time when the height of the ball is above the ground

  by 64 feet substitute h by 64

∵ h(t) = -16t² + 48t + 32

∵ h = 64

∴ 64 = -16t² + 48t + 32 ⇒ subtract 64 from both sides

∴ 0 = -16t² + 48t - 32 ⇒ multiply the both sides by -1

∴ 16t² - 48t + 32 = 0 ⇒ divide both sides by 16 because all terms have

  16 as a common factor

∴ t² - 3t + 2 = 0 ⇒ factorize it

∴ (t - 2)(t - 1) = 0

- Equate each bracket by zero to find t

∴ t - 2 = 0 ⇒ add 2 to both sides

∴ t = 2

- OR

∴ t - 1 = 0 ⇒ add 1 to both sides

∴ t = 1

- That means the ball will be at height 64 feet after 1 second when it

 moves up and again at height 64 feet after 2 seconds when it

 moves down

* There are two times for the ball to reach a height of 64 feet

  1 second after thrown ⇒ the ball moves upward

  2 seconds after thrown ⇒ the ball moves downward

3 0
2 years ago
A quality control officer randomly checking weights of pumpkin seed bags being filled by an automatic filling machine. Each bag
GarryVolchara [31]
From 0g to 494.7g are rejected as well as those heavier than 505.3grams.

You calculate this by subtracting and adding 5.3 to 500
7 0
1 year ago
Read 2 more answers
Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
30-1.50c+5c=54.50
5c-1.5c=54.50-30
3.5c=24.50
c=7

Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
2 years ago
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