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VLD [36.1K]
2 years ago
14

The function g(x) is a continuous quadratic function defined for all real numbers, with some of its values given by the table be

low.The quadratic function ƒ(x) is represented by the parabola below. x g(x) -3 0 -2 5 0 9 2 5 3 0 Select all the statements that are true. The function ƒ(x) has a maximum value at x = 4.5. The function g(x) has a minimum value of 0. The maximum value of g(x) is twice the maximum value of ƒ(x). Neither function has a minimum value.
Mathematics
1 answer:
abruzzese [7]2 years ago
8 0
Though I almost broke my brain while solving what "-3 0 -2 5 0 9 2 5 3 0" means, I can tell you which statements is absolutely incorrect: it is "The function g(x) has a minimum value of 0" (it is incorrect because the maximum value is 9 as table provides).
To solve other problems, look at f(x): if it has the top, where y is the biggest, then it is the maximum value (so if y = 4.5 is the biggest y, first statement is correct); if it has the bottom, where y is the smallest, then it is minimum value (factually, statement 3 will be correct if statement 1 is correct because 9/4.5 = 2). Finally, if f(x) has the top, then statement 4 is correct because f(x) and g(x) would be both constantly decreasing functions.
Hope this helps.
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3 > x OR x < 3 (3 is greater/bigger than x which also means x is smaller/lesser than 3)

They are both incorrect.
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2 years ago
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Jonah has a recipe that uses 1 1/2 cups of brown sugar and 2 1/3 cups of flour to make 24 muffins has a total of 7 cups of flour
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2 years ago
Part of the population of 7000 elk at a wildlife preserve is infected with a parasite. A random sample of 50 elk shows that 8 of
Nikolay [14]

Answer:

1120

Step-by-step explanation:

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Divide 50 on both sides

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2 years ago
A cardboard box without a lid is to have a volume of 16,384 cm3. Find the dimensions that minimize the amount of cardboard used.
Reika [66]

Answer:

The dimensions that minimize the amount of cardboard used is

x = 31 cm ,  y = 34 cm & Z = 15.54 cm

Step-by-step explanation:

Volume of the cardboard = 16,384 cm^{3}

The function that represents the area of the cardboard without a lid is given by

f (x,y,z) = xy + 2xz + 2yz ------  (1)

Volume of the cardboard with sides x, y & z is

xyz = 16384

z =  \frac{16384}{xy}

Put this value of z in equation (1) we get

f (x,y,z) = xy + 2x(\frac{16384}{xy} ) + 2y(\frac{16384}{xy} )

f (x,y,z) = xy + \frac{32768}{y}  + 2y(\frac{32768}{x} )

Differentiate above equation with respect to x & y we get

f_{x}  = y - \frac{32768}{x^{2} }

f_{y}  = x - \frac{32768}{y^{2} }

Take f_{x}  = 0 \ and  \ f_{y} = 0

y - \frac{32768}{x^{2} } = 0

y = 32768 \ x^{-2}  ------ (2)

x - \frac{32768}{y^{2} } = 0

x = 32768 \ y^{-2}  ------- (3)

By solving equation (2) & (3) we get

x^{3} = 32768

x = 31 cm

From equation 2

y = 32768 \ x^{-2}

y = 32768 (31^{-2})

y = 34 cm

z =  \frac{16384}{xy}

z =  \frac{16384}{(34)(31)}

Z = 15.54 cm

Thus the dimensions that minimize the amount of cardboard used is

x = 31 cm ,  y = 34 cm & Z = 15.54 cm

6 0
2 years ago
Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal
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Answer:

0.0359

Step-by-step explanation:

Data provided:

mean values of three independent times are 15, 30, and 20 minutes

the standard deviations are 2, 1, and 1.6 minutes

Now,

New Mean = 15 + 30 + 25 = 65

Variance = ( standard deviation )²

or

Variance = 2² + 1² + 1.6² = 7.56

therefore,

Standard deviation = √variance

or

Standard deviation =  2.75

Thus,

Z-value = \frac{\textup{60 - 65}}{\textup{2.75}}

or

Z-value = - 1.81

from the Z-table

the Probability of Z ≤ -1.81 = 0.0359

6 0
2 years ago
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