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FrozenT [24]
2 years ago
12

In a theater there are 12 chairs in the first row, each row has 2 more chairs than the previous row, and there are 10 rows. How

many chairs are there in the theate
Mathematics
1 answer:
Monica [59]2 years ago
7 0

Answer:

  210

Step-by-step explanation:

The first term of the sequence, a1, is 12. The common difference, d, is 2. The number of terms is n = 10. The sum is given by the formula ...

  Sn = (2a1 +d(n-1))(n/2)

Filling in the numbers, this is ...

  S10 = (2·12 +2(10-1))(10/2) = (24+18)(5) = 210

There are 210 chairs in the theatre.

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They are linear pairs, because they are adjacent and supplementary. Adjacent angles share a side – in this case, LN. Supplementary angles sum 180°, which you can see is right because the other sides (ML and RL) are in the same line. RLN and MLN sum the same as the size of RLM, which is a line, so it’s 180°.  <span>

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2 years ago
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A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inche
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Answer:

The correct option is

A.  \ \dfrac{1}{c} \times \left | x - 5 \right | = 0.3

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is \dfrac{1}{c} \times \left | x - 5 \right | = 0.3 or \left | x - 5 \right | = 0.3 \times c which gives the correct option as A

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