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disa [49]
1 year ago
9

In the figure, ABC DFE. What is the perimeter of ABC in inches?

Mathematics
1 answer:
lys-0071 [83]1 year ago
7 0

Answer:

Step-by-step explanation: 54in

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What is the product (6r-1)(-8r-3)
eimsori [14]
Use the FOIL method (First, Outside, Inside, Last)

6r(-8r) = -48r²
6r(-3) = -18r
-1(-8r) = 8r          (note: two negatives multiplied together = positive answer)
-1(-3) = 3

-48r² - 18r + 8r + 3

Combine like terms:


-48r² - 18r + 8r + 3

-48r² - 10r + 3


-48r² - 10r + 3 is your answer

hope this helps
6 0
2 years ago
Solve 5/3x + 1/3x = 13 1/3 + 8/3x then identify x.
belka [17]

After solving \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x we get value of x = -20

Step-by-step explanation:

We need to solve the fractions and find value of x.

The given fraction is:

\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x

Solving:

\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x\\\frac{5}{3}x+\frac{1}{3}x=\frac{40}{3}+\frac{8}{3}x\\ Subtract\,\,\frac{8}{3}x\,\,on\,\,both\,\,sides:\\ \frac{5}{3}x+\frac{1}{3}x-\frac{8}{3}x=\frac{40}{3}+\frac{8}{3}x-\frac{8}{3}x\\Simplifying:\\ \frac{5x+1x-8x}{3}=\frac{40}{3}\\ \frac{-2x}{3}=\frac{40}{3}\\Multiply\,\,both\,\,sides\,\,by\,\,3\\-2x=40\\x=\frac{40}{-2}\\x=-20

So, After solving \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x we get value of x = -20

Keywords: Solving fractions

Learn more about Solving fractions at:

  • brainly.com/question/2456302
  • brainly.com/question/1648978
  • brainly.com/question/13168205

#learnwithBrainly

3 0
2 years ago
Estimated quotient of 119÷23​
masha68 [24]

Answer:

5...................

8 0
1 year ago
Read 2 more answers
Hey! i’ll give brainliest please help
miss Akunina [59]

Answer:

D

Step-by-step explanation:

8 0
1 year ago
Which equation is the inverse of y = 16x2 + 1? y = plus-or-minus StartRoot StartFraction x Over 16 EndFraction minus 1 EndRoot y
kifflom [539]

Answer:

The inverse is ±sqrt((x-1))/ 4

Step-by-step explanation:

y = 16x^2 + 1

To find the inverse, exchange x and y

x = 16 y^2 +1

Then solve for y

Subtract 1

x-1 = 16 y^2

Divide by 16

(x-1)/16 = y^2

Take the square root of each side

±sqrt((x-1)/16) = sqrt(y^2)

±sqrt((x-1))/ sqrt(16) = y

±sqrt((x-1))/ 4 = y

The inverse is ±sqrt((x-1))/ 4

8 0
1 year ago
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