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34kurt
2 years ago
15

If the area of a garden is 11 square feet what could be the dimensions of the garden

Mathematics
1 answer:
sergejj [24]2 years ago
7 0
Assuming that the garden is rectangular in shape, the area of a rectangle is given by length x width.

11 is a prime with factors 1 and 11.

Therefore, if the area of a (rectangular) garden is 11 square feet, then the possible dimension of the garden is 1 feet by 11 feet.
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A summer camp cookout is planned for the campers and their families. There is room for 200 people. Each adult costs $4, and each
Sati [7]

Answer:

A.\\\\x+y\leq200\\\\4x+3y\leq750

Step-by-step explanation:

x - number of adults

y - number of campers

<em>The room for 200 people</em>: x + y ≤ 200

<em>Each adult costs $4, and each camper costs $3</em>: 4x and 3y

<em>A maximum budget of $750</em>: 4x + 3y ≤ 750

5 0
2 years ago
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Last year Lenny had an annual earned income of $58,475. He also had passive income of $1,255, and capital gains of $2,350. What
Lelechka [254]

<u>Answer:</u>  d. $62,080

<u>Step-by-step explanation:</u>

<u></u>

The capital gain is the profit earned from an investment whereas the passive income is the income generated by very minimal daily efforts.

Given: Annual income earned by Lenny = \$58,475

Passive income =  \$1,255

Capital gain =  \$2,350

Now,  \text{Total gross income =Annual income+Passive income+Capital gain}

=\$58,475+\$1,255+\$2,350=\$62,080

Hence, Lenny's total gross income for the year = $62,080

4 0
1 year ago
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A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 9 1/3 squar
Vika [28.1K]
Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd

Area of parallelogram = base * height

We need to divide the combined area into two to get each parallelogram's base.

9 1/3 = ((9*3)+1)/3 = 28/3

28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²

Area of each parallelogram is 4 2/3 yd²

4 2/3 yd² = base * 1 1/3 yd

14/3 yd² ÷ 4/3 yd = base

14/3 yd² x 3/4 yd = base
14*3 / 3*4 = base
42 / 12 = base
3 6/12 yd = base
or 3 1/2 yd = base

a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.

length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds

Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²


8 0
1 year ago
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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 I k
jonny [76]
Check the picture below.

3 0
1 year ago
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Given: AD ≅ BC and AD ∥ BC Prove: ABCD is a parallelogram. Statements Reasons 1. AD ≅ BC; AD ∥ BC 1. given 2. ∠CAD and ∠ACB are
ira [324]

 Given: AD ≅ BC and AD ∥ BC

Prove: ABCD is a parallelogram.

 Statements                                                                 Reasons

 1. AD ≅ BC; AD ∥ BC                                              1. given

 2. ∠CAD and ∠ACB are alternate interior ∠s          2. definition of alternate                                                                                    interior angles

3. ∠CAD ≅ ∠ACB                                                    3. alternate interior                                                                                          angles are congruent

4. AC ≅ AC                                                              4. reflexive property

 5. △CAD ≅ △ACB                                                  5. SAS congruency                                                                                                   theorem

6. AB ≅ CD                                                            6. Corresponding Parts                                                                                   of Congruent triangles are                                                                               Congruent (CPCTC)

7. ABCD is a parallelogram                                  7. parallelogram side                                                                                         theorem

<span> </span>

5 0
2 years ago
Read 2 more answers
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