All categories

2 years ago

m∠RSW = 2x + 16; m∠WSV = 3x + 2 m∠UST = 2x; m∠VSU = m∠UST Find m∠WSV. please answer this geotemrty is really hard

Mathematics

1 answer:

stepladder [879]2 years ago

8 0

Answer: 56 degree

Explanation:

2x + 16 + 3x + 2 + 2x + 2x = 180 (straight angle)

9x + 18 = 180
9x = 162
x = 162/9
x = 18

But WSV = 3x + 2

And x = 18

=> 3(18) + 2
=> 54 + 2 = 56

You might be interested in

Altitude above sea level is given in positive values and below sea level is given in negative values. Which situation describes

grin007 [14]

A because if he started at negative ten you would add the 10 he increased. When you add those two together you get 0.

-10+10=0

6 0

2 years ago

Read 2 more answers

Explain why sin^-1(sin(3pi/4))does not equal 3pi/4 when y=sin x and y=sin^-1 x are inverses.

Fofino [41]

Because they're not inverses, not exactly. $\sin x$ is not invertible on its entire domain because it's not one-to-one. There are infinitely many values of $x$ such that $\sin x=0$ , for example.

The standard function $\sin^{-1}x$ has a domain of $-1\le x\le1$ and outputs values between $-\dfrac\pi2$ and $\dfrac\pi2$ . This means that its inverse, $\sin x$ , is indeed its inverse as long as $-\dfrac\pi2\le x\le\dfrac\pi2$ .

$\dfrac{3\pi}4$ is larger than $\dfrac\pi2$ and thus does not fall in the "invertible part" of the domain of $\sin x$ . We have

$\sin\dfrac{3\pi}4=\dfrac1{\sqrt2}$

which is a value between -1 and 1, so that

$\sin^{-1}\left(\sin\dfrac{3\pi}4\right)=\sin^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

If we wanted to recover $\dfrac{3\pi}4$ , we'd have to redefine $\sin^{-1}x$ or define a new inverse function that works on a different branch of the domain of $\sin x$ .

7 0

2 years ago

A store sells both cold and hot beverages. Cold beverages, c, cost $1.50, while hot beverages, h, cost $2.00. On Saturday, drink

Marina86 [1]

2h + 4h (1.5c) = 360 so option b is correct.

3 0

2 years ago

Read 2 more answers

A lightbulb manufacturer ships large consignments of lightbulbs to big industrial users. When the production process is function

Mashutka [201]

Answer:

a) P[ Pf | Ptd ] = 0,428

b) P[ Pf | Nd ] = 0,692

Step-by-step explanation:

We will call:

Pf Probability of functioning correctly 60 % or 0.6

Pfn Probability of malfunctioning 40 % or 0,4

PNd Probability of nondefective bulb

D₁ Probability of defective bulb when the process is correctly working

D₂ Probability of defective bulb when the process is in malfunction condition

Ptd Total probability of defective bulbs

Then applying theorem´s Bayes have

P [ A | B ] = P(A) * P [ B | A ] / P(B)

a) Probabilty of the process is functioning correctly given that we pick up a defective bulb

The total probability of defective bulbs is equal to, probabilty of defective bulbs when the process is Ok, plus probability of defective bulbs when the process is in malfunctioning condition, therefore

Ptd = (0,6)*(0,25) + (0,40)*(0,50) = 0,15 * 0,20 = 0,35

P[ Pf | Ptd ] = Pf * P [ Pd | Pf ] / Ptd = 0,6 * 0,25 / 0,35

P[ Pf | Ptd ] = 0,428

b) P [ Pf | Nd ]

P[ Pf | Nd ] = Pf * P [Nd | Pf ] / PNd

PNd = 1 - Ptd = 1 - 0,35 = 0,65

P[ Pf | Nd ] = 0,6 * 0,75 / 0,65 = 0,692

P[ Pf | Nd ] = 0,692

6 0

2 years ago

Point C(3.6, -0.4) divides AB in the ratio 3:2. If the coordinates of A are (-6, 5), the coordinates of point B are ___. If poin

kari74 [83]

When a point divides a line segment into ratios of k1:k2, the formula to find the coordiates of the point is:
x=(k2*x1+k1*x2)/(k1+k2), y=(k2*y1+k1*y2)/(k1+k2),
(x1,y1) being the coordinates of the starting point, and (x2,y2) coordinates of the end point.
in this case, 3.6=[2*(-6)+3x2]/5
-12+3x2=18
3x2=30
x2=10

use the same method to find y2: -0.4=(2*5+3y2)/5
3y2=-12
y2=-4
so the the coordinates of B is (10,-4)

use the same method to find the coordinates of D.

the answer I've got for D is (58/9, -2) please double check my calculation.

4 0

2 years ago

Read 2 more answers