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strojnjashka [21]

1 year ago

10

A 1500 kg hippo is completely submerged, standing on the bottom of a lake. What is the approximate value of the upward normal fo

rce on the hippo?

1 answer:

juin [17]1 year ago

7 0

Answer:

About 428 N

Step-by-step explanation:

Weight = 1,500 * 9.8 = 14,700 N

Density = Mass ÷ Volume

1,030 = 1,500 ÷ V

V = 1,500 ÷ 1,030 = 1.46 m^3.

Buoyant force = Density * g * V

Buoyant force = 1,000 * 9.8 * (1,500 ÷ 1,030)

Buoyant force = 9,800 * (1,500 ÷ 1,030) = 14,272 N.

Net force = 14,700 – [(9,800 * (1,500 ÷ 1,030)]

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The graph of which function is decreasing over the interval (–4, ∞)?

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Ann took a taxi home from the airport. The taxi fare was \$2.10$2.10dollar sign, 2, point, 10 per mile, and she gave the driver

Studentka2010 [4]

Answer:

$2.10x+5=49.10$

Distance = 21 miles.

Step-by-step explanation:

Let x be the distance in miles between the airport and Ann's home.

We have been given that Ann took a taxi home from the airport. The taxi fare was $2.10 per mile. So fare for x miles will be 2.10x.

We are also told that she gave the driver a tip of $5. Ann paid a total of $49.10. This means that fare of x miles and tip given to driver equals $49.10. We can represent this information in an equation as:

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Now let us solve our equation.

$2.10x=49.10-5$

$2.10x=44.10$

$x=\frac{44.10}{2.10}=21$

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1 year ago

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The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

Ierofanga [76]

Answer:

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beks73 [17]

Answer:

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Multiply this expression by 10.

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AnnZ [28]

Answer:

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Step-by-step explanation:

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