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Butoxors [25]
2 years ago
12

Which algebraic expression is a polynomial? 4x2 – 3x + StartFraction 2 Over x EndFraction –6x3 + x2 – StartRoot 5 EndRoot 8x2 +

StartRoot x EndRoot –2x4 + StartFraction 3 Over 2 x EndFraction
Mathematics
2 answers:
rusak2 [61]2 years ago
7 0

Answer:

The Answer is B

Step-by-step explanation:

Veseljchak [2.6K]2 years ago
3 0

Answer:

B.-6x^3+x^2-\sqrt5

Step-by-step explanation:

Polynomial of one variable:It is that expression in which power of each variable in the given should be a whole number.The highest power of variable is called degree of polynomial.

Power of  variable in given terms cannot be negative or fraction.

A.4x^2-3x+\frac{2}{x}

It can be write as

4x^2-3x+2x^{-1}

By definition of polynomial of one variable , it is not a polynomial.

B.-6x^3+x^2-\sqrt5

By definition of polynomial of one variable , it is a  polynomial.

C.8x^2+\sqrt{x}

By definition of polynomial of one variable, it is not  a polynomial.

D.-2x^4+\frac{3}{2x}

By definition of polynomial of one variable,it is not  a polynomial.

Hence, option B is true.

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The average length of a king cobra is 3.7 m. The record length is 1.88 m longer than the average. How long is the record holder?
Ugo [173]

Answer:

The record holder is 5.58 m.

Step-by-step explanation:

3.7+1.88=5.58


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What is the place value of 3 in 9. 365?​
nikdorinn [45]

Answer:

It is in the tenths place

Step-by-step explanation:

In the number 9.365, 3 is in the tenths place.

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1 year ago
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Find the sum of the first 63 terms of –19, -13, -7 …
boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

Given n = 63 and we found a = -19 and d = 6

\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)

\implies S_6_3 = \frac{63}{2}(-38 + (62)6)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(334)

\implies S_6_3 = {63}(167) = 10521

The Sum of First 63 terms is 10521

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Write 12,430,090in expanded form
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400,000+30,000+90
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Supervisor: "Last week, you spoke with 800 customers in 40 hours."
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