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Aloiza [94]
2 years ago
11

Ashton surveyed some of the employees at his company about their cell phone habits. From the data, he concluded that most employ

ees at his company use cell phones primarily for business. For which sample could this generalization be valid?
A. all managers in the company
B. some managers and some sales executives selected at random
C. every fifth employee on the employee list
D. every other sales executive on the employee list
Mathematics
1 answer:
SOVA2 [1]2 years ago
3 0
It can't be A. since if you only look at managers, you are missing all the sales executives.

It may be C. this option is more random but doesn't guarantee that you will represent both groups of employee's. Also, each time you would conduct the survey, you will receive the exact same results since it is the same people. 

It isn't D. for the exact same reason as A. but you're missing managers now. 

Therefore the answer is B. Some managers and some sales executives selected at random. This way you get a sample from both categories, and within those groups, it is randomly selected.

 I hope this helps!

 
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Drag the values to order them from least to greatest, with the least at the top. Item 2 moved to position 3. 79 − − √ + 63 − − √
Nonamiya [84]

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi

By using calculator, let's convert those numbers into decimal form:

\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56

So arranging from least to greatest we have:

\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

Put another way:

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

7 0
1 year ago
Justin traveled 70 miles from Boston to Hyannis in 1 hr and 45 minutes. He then traveled 10 more miles from Hyannis to Dennispor
Veseljchak [2.6K]

Answer:

40 mph first one

Step-by-step explanation:

4 0
1 year ago
Melanies fruit punch recipe calls for 6 cups of apple juice for every 3 cups os carrot juice how many cups os carrot juice are u
olchik [2.2K]
Well 3 is half of 6, so half of one is 1/5
5 0
2 years ago
Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
musickatia [10]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

8 0
2 years ago
A Cepheid star is a type of variable star, which means its brightness is not constant. The relationship between the brightness o
White raven [17]

Answer:

The absolute brightness of the Cepheid star after a period of 45 days is -5.95

Step-by-step explanation:

Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by

M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.

From our question, it is given that P = 45 days.

So, M = –2.78(log P) – 1.35

M = –2.78(log 45) – 1.35

M = –2.78(1.6532) – 1.35

M = -4.60 - 1.35

M = -5.95

So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95

8 0
2 years ago
Read 2 more answers
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