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rodikova [14]
2 years ago
7

Suppose that a teacher wishes to distribute 25 identical pencils to Ahmed, Barbara, Casper, and Dieter such that Ahmed and Diete

r receive at least one pencil each, Casper receives no more than five pencils, and Barbara receives at least four pencils. In how many ways can such a distribution be made?
Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

we will change the problem in stages

pre-place 1 in x1 & x4, and 4 in x2, thus guaranteeing their minimum requirements.

now 19 pencils remain to be distributed

when there are no restrictions on distributing n identical objects to k distinct piles, the formula is (n+k-1)C(k-1) which here translates to 22C3

finally, we need to see that x3 = 5, so we place 6 in x3 (guaranteeing that it violates the condition), and subtract such violations, ie (22-6)C3 = 16C3

ans: 22C3 - 16C3 = 980

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Which points are plotted correctly on their accompanying number line? Check all that apply. Point: Negative StartFraction 7 Over
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What key would you use if 10 students chose cartoons
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Use polar coordinates to find the volume of the given solid. bounded by the paraboloid z = 9 + 2x2 + 2y2 and the plane z = 15 in
mina [271]

Answer:

Z = 8 + 2x2 + 2y2

Convert to polar coordinates

Z = 8 + 2r2

Now theta will go from 0 to pi/2 because it's in the first quadrant.

R will go from 0 to the radius of the circle formed at the intersection of the plane and the paraboloid.

14 = 8 + 2r2

r = sqrt(3)

So r goes from 0 to sqrt(3).

You integrate 14-z where 0<r<sqrt(3) and 0<theta<pi/2.

It is 14-z and not z because just z would give the volume under the paraboloid.

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5 0
2 years ago
Soup ordinarily priced at 2 cans for .33 cents may be purchased in lots of one dozen for 1.74, what is the savings per a can whe
Sidana [21]

Answer:

Savings per can would be 0.02 cents when purchased in lots.

Step-by-step explanation:

Given:

Ordinary price of soup 2 cans = 0.33 cents.

When purchases in lots 12 cans = 1.74

We need to find the saving per can when purchased in Lots.

Solution:

Ordinary price of soup 2 cans = 0.33 cents.

1 can  = Cost of 1 can when purchased ordinary.

By Using Unitary method we get;

Cost of 1 can when purchased ordinary = \frac{0.33}{2} = 0.165\ cents/can

Now we will find the Cost of 1 can when purchased in lot.

12 cans = 1.74

1 can = Cost of 1 can when purchase in lot.

Again by using Unitary method we get;

Cost of 1 can when purchase in lot = \frac{1.74}{12} = 0.145\ cents/can

Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary

Savings = 0.165-0.145=0.02\ cents/can

Hence Savings per can would be 0.02 cents when purchased in lots.

5 0
2 years ago
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