A funnel is made up of a partial cone and a cylinder as shown in the figure. The maximum amount of liquid that can be in the fun
2 answers:
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Answer:
0.2%
Step-by-step explanation:
The given parameters are;
The percentage of product within the correct range = 95%
The percentage of the times the sensor reject boxes of incorrect weight = 98%
The percentage of the times the company reject boxes with correct weight = 1%
We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2
FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01
FPR = 0.2/(0.2 + 9.8) = 0.02
TPR = 89.1/(89.1 + 0.9) = 0.99
TNR = 9.8/(9.8 + 0.2) = 0.98
P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))
Where;
P(C/A) = The probability that a correct weight package is accepted
∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776
The probability that a correctly weighed package is rejected, P(C/R), is given as follows;
P(C/R) = 1 - P(C/A)
∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%
The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%
<u>Given</u>:
The given balanced scale is represented by the equation
----- (1)
We need to determine the process that balance the scale.
<u>Process to balance the scale:</u>
Given that the if one x block is subtracted from the right side and three numbered blocks are subtracted from the left side.
Thus, the equation (1) becomes
----- (2)
Now, to balance the scale, let us subtract one block x from the left side and subtract three numbered blocks from the right side.
Thus, the equation (2) becomes,
------ (3)
Thus, the equation (3) is the same as the equation (1).
Hence, the process required to balance the scale is to subtract one x block from the left side and subtract three numbered blocks from the right side.
Therefore, Option B is the correct answer.