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Readme [11.4K]
2 years ago
6

A 6 foot long board is propped against the wall of a house. The board forms a 60 degree angle with the ground. How far is the ba

se of the board from the wall
Mathematics
1 answer:
Zarrin [17]2 years ago
6 0
To solve this problem you must apply the proccedure shown below:
 1. You have that  the lenght ot the board is 6 feet and <span> forms a 60 degree angle with the ground. Therefore, you have:
 Sin</span>α=opposite/hypotenuse
 α=60°
 opposite=x
 hypotenuse=6
 2. When you substitute the values, you obtain:
 Sin(60°)=x/6
 3. Now, you must solve for x, as following:
 x=6Sin(60°)
 x=5.19
 Therefore, the answer is: 5.19 feet.
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A rectangular board is 1.8 meters long and 1.25 meters wide. What is the area of the board in square millimeters? Do not round y
lilavasa [31]

Answer:

2250000 mm^2 or 2.25 m^2

Step-by-step explanation:

Area=1.8*1.25=2.25 m^2=2250000 mm^2

7 0
1 year ago
What is the numerator of the simplified sum? StartFraction x Over x squared + 3 x + 2 EndFraction + StartFraction 3 Over x + 1 E
ozzi

Answer:

4x + 6

Step-by-step explanation:

Given

\frac{x}{x^2+3x+2} + \frac{3}{x+1}

Before we can add the fractions we require them to have a common denominator.

Factor the denominator of the first fraction

\frac{x}{(x+1)(x+2)} + \frac{3}{x+1}

Multiply the numerator / denominator of the second fraction by (x + 2)

= \frac{x}{(x+1)(x+2)} + \frac{3(x+2)}{(x+1)(x+2)} ← fractions now have a common denominator

Add the numerators leaving the denominators

= \frac{x+3(x+2)}{(x+1)(x+2)}

= \frac{x+3x+6}{(x+1)(x+2)}

= \frac{4x+6}{(x+1)(x+2)} ← simplified sum with numerator 4x + 6

7 0
2 years ago
Alonzo's suitcase can weigh no more than 20 kilograms if he wants to take it on the airplane without paying a fee. His suitcase
LiRa [457]
20 kilograms is 200 hectograms
The limit is 200 hectograms and his suitcase is 220 hectograms.
Subtract 220-200 and his suitcase is over by 20 hectograms.
He will have to remove 20 hectograms
6 0
2 years ago
Read 2 more answers
A football player kicks a football downfield. The height of the football increases until it reaches a maximum height of 15 yards
tino4ka555 [31]

Answer:

kick 1 has travelled 15 + 15 = 30 yards before hitting the ground

so kick 2 travels 25 + 25 = 50 yards before hitting the ground

first kick reached 8 yards and 2nd kick reached 20 yards  

Step-by-step explanation:

1st kick travelled 15 yards to reach maximum height of 8 yards

so, it has travelled 15 + 15 = 30 yards before hitting the ground

2nd kick is given by the equation

y (x) = -0.032x(x - 50)

y = 1.6 x - 0.032x^2

we know that maximum height occurs is given as

x = -\frac{b}{2a}

y = - \frac{1.6}{2( - 0.032)} = 25

and maximum height is

y = 1.6(25) - 0.032 (25)^2

y = 20

so kick 2 travels 25 + 25 = 50 yards before hitting the ground

first kick reached 8 yards and 2nd kick reached 20 yards  

6 0
2 years ago
Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so with
Stels [109]

Answer:

The possible value of X are;

15, 30, 45, 60 etc

Step-by-step explanation:

The parameters given are

Number of chocolates Tanmay had = X

Number of chocolates Tanmay gave to Akash = 1/3 × X

Number of chocolates Tanmay gave to Sharad = 1/5 × X

Whereby 3 and 5 are factors of X, therefore;

3 × 5 = 15 is the lowest single factor of X

The possible values of X starting from the lowest factor are given as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Hence, the possible value of X are the arithmetic progression a + (n - 1)×d

Where:

a = 15

n = 1, 2, 3, 4, ...

d = 15

Which includes;

15, 30, 45, 60

7 0
2 years ago
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