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Juliette [100K]
2 years ago
11

11. The Leonin family used 90 kWh for their electric consumption for the month of

Mathematics
1 answer:
almond37 [142]2 years ago
3 0

Answer:

The electric bill of the Leonin family was of $ 877,626.

Step-by-step explanation:

Given that the Leonin family used 90 kWh for their electric consumption for the month of August, if the power consumption costs P9.7514 per kWh, to determine how much is their electric bill, the following calculation must be performed:

9.7514 x 90 = X

877.626 = X

Thus, the electric bill of the Leonin family was of $ 877.626.

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Add all the units together 8+11+6+8=45
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Raleigh went to gaming arcade for his birthday. His parents gave him $55 to spend. He purchased $14.25 in food and drinks, and p
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Answer: he will be able to play 32.6 games at the arcade

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weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probabi
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Answer:

0.34134

Step-by-step explanation:

In other to solve for this question, we would be using the z score formula

z = (x - μ) / σ

x = raw score

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σ = Standard deviation

We are told in the question to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

From tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134

7 0
2 years ago
The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as
Rzqust [24]

Answer:

  109.9 ft

Step-by-step explanation:

The length of an arc that is 1/4 of a circle of radius 70 ft is ...

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A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sam
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Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

s=4.00

Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval : \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

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Required 95% confidence interval :  (15.263,\ 17.537)

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