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Elis [28]
2 years ago
10

According to Consumer Digest (July/August 1996), the probable location of personal computers (PC) in the home is as follows: Adu

lt bedroom: 0.03 Child bedroom: 0.15 Other bedroom: 0.14 Office or den: 0.40 Other rooms: 0.28 (a) What is the probability that a PC is in a bedroom? (b) What is the probability that it is not in a bedroom? (c) Suppose a household is selected at random from households with a PC; in what room would you expect to find a PC?
Mathematics
1 answer:
Andreas93 [3]2 years ago
6 0

Answer:

a) 0.32

b) 0.68

c) Office or den

Step-by-step explanation:

a) The probability that a PC is in a bedroom is the sum of the probabilities of a PC being is an adult bedroom, child bedroom or other bedroom:

P(B) =P(adult)+P(child)+P(other)\\P(B) = 0.03+0.15+0.14\\P(B) =0.32

b) The probability that a PC is not in a bedroom is 100% minus the probability of it being in a bedroom:

P(Not\ B) = 1- P(B)\\P(Not\ B) =1-0.32\\P(Not\ B) =0.68

c) The expected room to find a PC from a randomly selected household is the room with highest likelihood of having a PC according to Consumer Digest. The Office or den, is the most probable room with a 0.40 chance.

You would expect to find a PC in the Office or den.

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Answer: 25

Step-by-step explanation:

From the question, we are told that a producer of electronic book readers is performing a quality check to make sure that the reader's backlight is working correctly. Then, the plant manager tests 2,000 readers on Monday and finds that 8 have defective backlights. The fraction 1/x is the experimental probability of a book reader having a defective backlight. What is the value of x?

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Probability of having a defective backlight will be the number of defective backlight divided by the number of readers tested. This will be:

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kiruha [24]

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Step-by-step explanation:

I looked at it this way:

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In simpler terms:

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2 years ago
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