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Semmy [17]
2 years ago
6

The speed limit on a road is 60 mph. The actual speeds of cars are measured and found to be normally distributed with a mean val

ue of 63 mph and a standard deviation of 5 mph. Approximately what percentage of cars exceed the speed limit by more than 10 mph?
A) 5.0%
B) 6296%
C) 7.3%
D) 8.1%
Mathematics
1 answer:
Vladimir79 [104]2 years ago
6 0

Answer:  8.1%

Step-by-step explanation:

Given : \mu=63

\sigma=5

Let x be the random variable that represents the actual speeds of cars.

The speed limit on a road is 60 mph.

Using formula , z=\dfrac{x-\mu}{\sigma}, we have for x= 60+10=70

\dfrac{70-63}{5}=1.4

Using z-table for right-tailed test value, The probability of  cars exceed the speed limit by more than 10 mph will be

P(x>70)=P(z>1.4)=0.0807567\approx0.081=8.1\%

Hence, the percentage of cars exceed the speed limit by more than 10 mph is 8.1%.

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Answer:

-5/6

Step-by-step explanation:

-1 2/3=-5/3

-5/3+5/6=-10/6+5/6=-5/6

5 0
2 years ago
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if you're talking about the whole number, 100.96. if you're referring to decimal place values; 96.70.

underline the digit that you round to

circle the digit to the right

five or more goes up

four or less stays the same

everything behind becomes a zero.

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The green turtle lays eggs that are approximately spherical with an average diameter of 4.5 centimeters. each turtle lays an ave
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The average volume if these eggs will be found as follows:
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4 0
2 years ago
There are 10 pots exposed in the shop, 2 of which have hidden defects. the customer buys two pieces. what is the probability tha
Tpy6a [65]
Check the tree diagram, of all the possible scenarios and the probabilities.

All the possible scenarios are: 

1st.non defective,  2nd.non defective
1st.non defective,  2nd. defective
1st. defective,  2nd. non defective
1st. defective,  2nd. defective

consider the case 1st.non defective,  2nd.non defective

the probability that the first one is non defective is 8/10, since 8 out of 10 are non defective.

In this scenario, the second one is non defective as well. The probability for this to happen is 7/9, since now we have 7 non defective pots, and 9 in total.

This means that the probability of the first to be non defective, and the second non-defective is (8/10) * (7/9)=0.622

similarly we calculate the other cases, as shown in the picture.

P(at least one is defective)=
P(1st.non defective,  2nd. defective)+P(1st. defective,  2nd. non defective)+P(1st. defective,  2nd. defective)=
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Answer: 0.378

8 0
2 years ago
Farhan has three pieces of rope with lengths of 140cm, 168cm and 210cm. He wishes to cut all the three pieces of ropes into smal
kap26 [50]

Answer:

The greatest possible length is 14 cm.

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Step-by-step explanation:

The greatest common factor of these three numbers is 14.

Total number of smaller pieces = 10+12+15 = 37

Best Regards!

3 0
2 years ago
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