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Semmy [17]
2 years ago
6

The speed limit on a road is 60 mph. The actual speeds of cars are measured and found to be normally distributed with a mean val

ue of 63 mph and a standard deviation of 5 mph. Approximately what percentage of cars exceed the speed limit by more than 10 mph?
A) 5.0%
B) 6296%
C) 7.3%
D) 8.1%
Mathematics
1 answer:
Vladimir79 [104]2 years ago
6 0

Answer:  8.1%

Step-by-step explanation:

Given : \mu=63

\sigma=5

Let x be the random variable that represents the actual speeds of cars.

The speed limit on a road is 60 mph.

Using formula , z=\dfrac{x-\mu}{\sigma}, we have for x= 60+10=70

\dfrac{70-63}{5}=1.4

Using z-table for right-tailed test value, The probability of  cars exceed the speed limit by more than 10 mph will be

P(x>70)=P(z>1.4)=0.0807567\approx0.081=8.1\%

Hence, the percentage of cars exceed the speed limit by more than 10 mph is 8.1%.

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Since 26 people had a cold longer than 7 days, this means 60-26=34 had a cold that was less than or equal to 7 days.

14 people had a cold longer than 7 days and received medicine; this means that 26-14=12 people had a cold longer than 7 days and did not receive medicine.

30-14=16 people received medicine and had a cold less than or equal to 7 days.

30-12=18 people did not receive medicine and had a cold less than or equal to 7 days.

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The mass of the toddler is 12.5 kg.

Step-by-step explanation:

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Given that ; h= 1.5m, Ep=187.5J , g=10 N/kg then finding m;

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187.5=15m

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How do you convert 1.42 g/cm^2 to mg/mm^2 Step by Step?
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A psychologist would like to examine the effects of different testing methods on the final performance of college students. One
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Answer:

Check the explanation

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The null and alternative hypothesis for this one way ANOVA is given as below:

Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.

Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.

The ANOVA table with calculations can be seen in the attached images below:

In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.

In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.

3 0
1 year ago
the diagonal of a tv is 26 inches long assuming that this diagonal forms a tv pair 30-60-90 right triangles what are the exact l
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It is an application of Pythagorean Theorem

And it is clear that the lower angle is 30 and the apex angle is 60 (this is how always normal TVs look like) ... refer to the image I attached

So, to calculate the width and the length:

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You can after that round the length to be 22.517 in



Hope you got the idea

3 0
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