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2 years ago

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Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 5, the length of B C is 3, and the length

of A C is 4. What is the length of the side opposite Angle B? 3 units 4 units 5 units 6 units

1 answer:

svetoff [14.1K]2 years ago

5 0

The side opposite to angle B is the side that does not contact with angle B.

In this attached image, you can see better that sides AB and BC is in contact with angle B. So, the opposite side to angle B is AC.

Therefore, the lenght of the side opposite to angle B is 4 units.

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3x23=69 is the equation that has the sum 69

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En una cancha se va a pintar la circunferencia central que tiene un diámetro de 5 m .¿cual es la longitud de la circunferencia?

Alona [7]

Answer:

The length of the circumference is $5\pi\ m$ or $15.70\ m$

Step-by-step explanation:

<u><em>The question in English is</em></u>

On a court, the central circumference will be painted, which has a diameter of 5 m. What is the length of the circumference?

we know that

The circumference of a circle is given by the formula

$C=\pi D$

we have

$D=5\ m$

substitute

$C=\pi (5)\\C=5\pi\ m$

This is the exact value

assume

$\pi=3.24$

$C=5(3.14)=15.70\ m$

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2 years ago

Two samples each of size 20 are taken from independent populations assumed to be normally distributed with equal variances. The

Harlamova29_29 [7]

Answer:

$t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923$

The degrees of freedom are

$df=20+20-2=38$

And the p value is given by:

$p_v =2*P(t_{38}>2.923) =0.0058$

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

We have the following data given:

$n_1 =20$ represent the sample size for group 1

$n_2 =20$ represent the sample size for group 2

$\bar X_1 =43.5$ represent the sample mean for the group 1

$\bar X_2 =40.1$ represent the sample mean for the group 2

$s_1=4.1$ represent the sample standard deviation for group 1

$s_2=3.2$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$\S^2_p =\frac{(20-1)(4.1)^2 +(20 -1)(3.2)^2}{20 +20 -2}=13.525$

And the deviation would be just the square root of the variance:

$S_p=3.678$

The statistic is givne by:

$t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923$

The degrees of freedom are

$df=20+20-2=38$

And the p value is given by:

$p_v =2*P(t_{38}>2.923) =0.0058$

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

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2 years ago

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tino4ka555 [31]

Answer:

0.3425 = 34.25% probability it will be off probation in February 2020

Step-by-step explanation:

We have these desired outcomes:

Off probation in July 2019, with 0.25 probability, then continuing off in January, with 1 - 0.08 = 0.92 probability.

Still in probation in July 2019, with 1 - 0.25 = 0.75 probability, then coming off in January, with 0.15 probability.

What is the probability it will be off probation in February 2020?

$p = 0.25*0.92 + 0.75*0.15 = 0.3425$

0.3425 = 34.25% probability it will be off probation in February 2020

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2 years ago

A square rotated about its center by 360º maps onto itself at(1,2,3,4) different angles of rotation. You can reflect a square on

Sladkaya [172]

A square rotated about its center by 360º maps onto itself at 90°, 180°, 270° and 360° - 4 different angles of rotation.

You can reflect a square onto itself across two diagonals and two segments that connects the middlepoints of opposite sides - 4 different lines of reflection.

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2 years ago