M<1≠m<2
m<4≠m<6
m<3 + m<5 = 180° ≠ 90°
m<7≠m<8
Answer:
none of them.
Answer: X= -6
Hope it helps
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:

P(B) is the probability that the selected student plays basketball.
Then:

P(A and B) is the probability that the selected student plays soccer and basketball:

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
Answer:
75.2 degrees Fahrenheit
Step-by-step explanation:
F = StartFraction 9 Over 5 EndFraction C + 32
- Multiply the value of C by StartFraction 9 Over 5 EndFraction before adding 32.
- 24 Degrees Celsius is 75.2 Degrees Fahrenheit.
No I don’t think it’s possible