Answer:
The p-value here is 0.0061, which is very small and we have evidence that the girls' mean is higher than the boys' mean.
Step-by-step explanation:
We suppose that the two samples are independent and normally distributed with equal variances. Let
be the mean number of ring tones for girls, and
the mean number of ring tones for boys.
We want to test
vs
(upper-tail alternative).
The test statistic is
T =
where
.
For this case,
,
,
,
,
.
and the observed value is
t =
.
We can compute the p-value as P(T > 2.6309) where T has a t distribution with 20 + 20 - 2 = 38 degrees of freedom, so, the p-value is 0.0061. Because the p-value is very small, we can reject the null hypothesis for instance, at the significance level of 0.05.
Answer:
79.2 tons
Step-by-step explanation:
What must be done is to apply a proportion rule, taking into account what happened in the registry and what is wanted for this new year. In the following way we can calculate the amount of tons of oranges.
Powder concentrate Oranges
45 tons -------------------------> 54 Tons
66 tons -------------------------> X Tons
X = 66 * 54/45
X = 79.2, that is to say that 79.2 tons are necessary to produce 66 tons of powder concentrate to make juice.
This question is incomplete because it lacks the appropriate options
Complete Question
Fifteen percent of the students at Central High take Spanish, 12% take French, and 4% take both. If a student is selected at random, what is the
probability that the student takes Spanish or French?
A 31%
B. 27%
C. 23%
D. 19%
Answer:
C. 23%
Step-by-step explanation:
At Central High
From the question, we are told that:
Spanish = 15%
French = 12%
Spanish and French = 4%
French or Spanish = unknown
Therefore, the probability that a student at random takes Spanish or French
= P(Spanish) + P(French) - P(Spanish and French)
= 15% + 12% - 4%
= 27% - 4%
= 23%
Step-by-step explanatiosorry don't understand question be more specific