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Cloud [144]
2 years ago
10

Bill removed the ten of spades and the king of hearts from a deck of standard playing cards and threw them in the trash. There w

ere originally fifty two cards in the deck. Three days later, his friend James picks up the same deck of cards. How many cards are in the deck now?
Mathematics
1 answer:
AveGali [126]2 years ago
3 0

Answer:

Step-by-step explanation:

2 if you mean 1 of each so it would be 50 cards

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Answer:

C

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the answer on edgeunity

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2 years ago
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If f'(x)=2/x and f(sqrt(e))=5, then f(e)=
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f'(x)=\dfrac2x
\implies f(x)=\displaystyle\frac2x\,\mathrm dx=2\ln|x|+C

f(\sqrt e)=5\implies 5=2\ln|\sqrt e|+C
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2 years ago
A school teacher is worried that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the s
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Answer:

H0 ; μ ≤ 4 pCi/L

Ha ; μ > 4 pCi/L

The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L

H0 ; μ ≤ 4 pCi/L

The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.

Ha ; μ > 4 pCi/L

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L

H0 ; μ ≤ 4 pCi/L

The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.

Ha ; μ > 4 pCi/L

7 0
2 years ago
Antonio's toy boat is bobbing in the water under a dock. The vertical distance HHH (in \text{cm}cmstart text, c, m, end text) be
musickatia [10]

Answer: Time t = 33.0 seconds

Step-by-step explanation:

Given that the vertical distance H between the dock and the top of the boat's mast t seconds after its first peak is modeled by the function

H(t) = 5cos( 2π/3 ​t) − 35.5H

Where the maximum vertical distance = 5

At the down position, H(t) = 0

5cos( 2π/3 ​t) − (35.5/100)H = 0

5cos( 2π/3 ​t) − 0.355 × 5 =0

5cos( 2π/3 ​t) − 0.1775 = 0

5cos( 2π/3 ​t) = 0.1775

cos( 2π/3 ​t) = 0.1775/5

cos( 2π/3 ​t) = 0.355

2π/3 ​t = cos^-1 (0.355)

2π/3 ​t = 69.2

2πt = 69.2 × 3

2πt = 207.6

t = 207.6/2π

t = 33.0 seconds

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