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zhenek [66]
2 years ago
5

Annabelle arranged her 42 building blocks into 3 rows of 14 blocks. Then, she rearranged them into 6 rows of 7 blocks. What two

other factor pairs could Annabelle use to help her rearrange the blocks again? Explain your answer using complete sentences.
Mathematics
1 answer:
cupoosta [38]2 years ago
4 0

Answer:

21 rows 2 blocks

1 row 42 blocks

Step-by-step explanation:

Given that:

Number of blocks with Annabelle = 42

First arrangement = 3 rows 14 blocks

Second arrangement = 6 rows 7 blocks

To find:

The other two factor pairs that could be used to rearrange the blocks again?

Solution:

Here, we will have to find the factor pairs of total number of blocks present with Annabelle.

i.e. 42

First of all, let us have a look at the factor pairs of 42.

42 = 3\times 14\\42 = 6\times 7\\42 = \underline{2\times 21}\\42 = \underline{1\times 42}

Therefore, the other two factor pairs can be 2, 21 and 1, 42.

The other two possible factor pairs are:

21 rows 2 blocks

1 row 42 blocks

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The shape below is constructed from six squares, and the lengths of the sides of the three smallest squares are written inside o
Maurinko [17]

Answer:

78

Step-by-step explanation:

Smallest square: 1

Small Square: 2, Area of 4

Mid Square: 3, Area of 9

Mid White Square: 5, Area of 25

Big Square: 8, Area of 64

1 + 4 + 9 + 64 = 78

5 0
2 years ago
Sheila has $47 to buy graphing pads for her math class. Each pad costs $8,
bija089 [108]

Answer:

5 tablets can be bought

Step-by-step explanation:

47/8= 5

8 0
2 years ago
Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribu
Svetllana [295]

Answer:

Step-by-step explanation:

Hello!

You have the variable

X: Area that can be painted with a can of spray paint (feet²)

The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²

since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.

a.

P(X>27)

First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)

P(Z>(27-25)/3)

P(Z>0.67)

Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of P(Z, you have to do the following conervertion:

P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143

b.

There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².

The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:

X[bar]~N(μ;δ²/n)

So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)

To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.

c.

P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999

d.

No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.

I hope it helps!

4 0
2 years ago
Janelle practices basketball every afternoon in the driveway each day her goal is to make four more baskets then she made the da
Alla [95]
She made 62 baskets by day 14. 4×13=52+10=62
5 0
2 years ago
a ball is thrown with a slingshot at a velocity of 110ft/sec at an angle of 20 degrees above the ground from a height of 4.5 ft.
satela [25.4K]

Answer:

t=2.47\ s  

Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

h(t) = h_0 + s_0t -16t ^ 2

Where h_0 is the initial height, s_0 is the initial velocity and t is the time in seconds.

We know that the initial height is:

h_0 = 4.5\ ft

The initial speed is:

s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s

So the equation is:

h (t) = 4.5 + 37.62t -16t ^ 2

The ball hits the ground when when h(t) = 0

So

4.5 + 37.62t -16t ^ 2 = 0

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

at^2 +bt + c

The quadratic formula is:

t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}

In this case

a= -16\\\\b=37.62\\\\c=4.5

Therefore

t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}

t_1=-0.114\ s\\\\t_2=2.47\ s  

We take the positive solution.

Finally the ball takes 2.47 seconds to touch the ground

4 0
2 years ago
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