Answer:
The error she made was that she was adding x and 2.75. She should subtract 2.75 from x.
Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.
Step-by-step explanation:
The error she made was that she was adding x and 2.75.
She should write the equation as 8 (x - 2.75) = 78; as she spends $2.75 to make a necklace.
By using the correct equation: 8 (x - 2.75) = 78
=> 8x - 22 = 78
=> 8x = 78 + 22
=> 8x = 100
=> x = 100/8
=> x = 12.5
Another mistake that she made was that she sold each for $7 assuming that she would make a profit of 78, but she should see each necklace for $12.5 so that she could make a profit of $78.
Hope this helps you.
Answer: Time t = 33.0 seconds
Step-by-step explanation:
Given that the vertical distance H between the dock and the top of the boat's mast t seconds after its first peak is modeled by the function
H(t) = 5cos( 2π/3 t) − 35.5H
Where the maximum vertical distance = 5
At the down position, H(t) = 0
5cos( 2π/3 t) − (35.5/100)H = 0
5cos( 2π/3 t) − 0.355 × 5 =0
5cos( 2π/3 t) − 0.1775 = 0
5cos( 2π/3 t) = 0.1775
cos( 2π/3 t) = 0.1775/5
cos( 2π/3 t) = 0.355
2π/3 t = cos^-1 (0.355)
2π/3 t = 69.2
2πt = 69.2 × 3
2πt = 207.6
t = 207.6/2π
t = 33.0 seconds
Answer:
Linear
For an increase of 1 in the x-value, what is the increase in the y-value? 2
Answer:
2 x plus 3 y equals 26. X plus 4 y equals 18
Step-by-step explanation:
Number of tiles, = x
Number of pints of paint, = y
Store 1:
Cost per tile = $2 ; cost per pint = $3 ; total cost = $26
Store 2 :
Cost per tile = $1 ; cost per pint = $4 ; total cost = $18
System of equation:
2x + 3y = 26 - - - (1)
x + 4y = 18 - - - - - (2)
The volume of a spherical shaped object is given by
Given that the <span>solid ball has a radius of 20.0 millimeters, the volume of the solid ball is given by
Therefore, the </span><span>closest to the volume of the synthetic compound ball, in cubic millimeters is 33,500 cubic milimeters.</span>
