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2 years ago

8

Greg builds a new pond which has a volume of 7.35m3, it is 4.2m long and 50cm deep, what is the width of the pond

1 answer:

nekit [7.7K]2 years ago

6 0

It is 3.5 meters wide

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If x+y=3 , x²+y²=5 then xy is what

tigry1 [53]

Xy is (1,2) because 1+2=3 and 1^2+2^2=5 therefor ur answer is xy= (1,2)

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2 years ago

A glass ball is packed in the box shown. Which expression represents the volume of foam padding needed to fill the space in the

zhuklara [117]

Answer: (27- 4/3 pi) r^3

Step-by-step explanation: 1. Volume of a cube: V= a^3, V= 3^3 , V=27

2. Volume of a sphere: V=4/3 pi r^3 ......

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2 years ago

Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point $B(5,2)\ C(7,-5)$

Find the slope BC

Substitute the values in the formula

$m=\frac{-5-2}{7-5}$

$m=\frac{-7}{2}$

$m=-3.5$

so

The equation $y=-3.5x-15$ is parallel to the line passing through the points $B(5,2)\ C(7,-5)$

therefore

<u>the answer Part A) is</u>

$B(5,2)\ C(7,-5)$ ------> $y=-3.5x-15$

<u>Case B)</u> Point $D(11,6)\ E(5,9)$

Find the slope DE

Substitute the values in the formula

$m=\frac{9-6}{5-11}$

$m=\frac{3}{-6}$

$m=-0.5$

so

The equation $y=-0.5x-3$ is parallel to the line passing through the points $D(11,6)\ E(5,9)$

therefore

<u>the answer Part B) is</u>

$D(11,6)\ E(5,9)$ ------> $y=-0.5x-3$

<u>Case C)</u> Point $F(-7,12)\ G(3,-8)$

Find the slope FG

Substitute the values in the formula

$m=\frac{-8-12}{3+7}$

$m=\frac{-20}{10}$

$m=-2$

so

Any linear equation with slope $m=-2$ will be parallel to the line passing through the points $F(-7,12)\ G(3,-8)$

<u>Case D)</u> Point $H(4,4)\ I(8,9)$

Find the slope HI

Substitute the values in the formula

$m=\frac{9-4}{8-4}$

$m=\frac{5}{4}$

$m=1.25$

so

The equation $y=1.25x+4$ is parallel to the line passing through the points $H(4,4)\ I(8,9)$

therefore

<u>the answer Part D) is</u>

$H(4,4)\ I(8,9)$ ------> $y=1.25x+4$

<u>Case E)</u> Point $J(7,2)\ K(-9,8)$

Find the slope JK

Substitute the values in the formula

$m=\frac{8-2}{-9-7}$

$m=\frac{6}{-16}$

$m=-0.375$

so

Any linear equation with slope $m=-0.375$ will be parallel to the line passing through the points $J(7,2)\ K(-9,8)$

<u>Case F)</u> Point $L(5,-7)\ M(4,-12)$

Find the slope LM

Substitute the values in the formula

$m=\frac{-12+7}{4-5}$

$m=\frac{-5}{-1}$

$m=5$

so

The equation $y=5x+19$ is parallel to the line passing through the points $L(5,-7)\ M(4,-12)$

therefore

<u>the answer Part F) is</u>

$L(5,-7)\ M(4,-12)$ ------> $y=5x+19$

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2 years ago

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Arti is mixing some orange paint for the class mural.

vitfil [10]

Answer:

6

Step-by-step explanation:

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2 years ago

Compare and contrast XY with XY.

mojhsa [17]

Answer:

${}$ XY $\overline {XY}$

Represent a distance ${}$ √

Represent a segment ${}$ √

Represent a numerical value ${}$ √

Represent a geometric figure √

Can be found by applying the ruler postulate ${}$ √

Can be be duplicated with a compass and a straight edge √

Step-by-step explanation:

The difference between XY and $\overline {XY}$ are that the points XY represents the distance between two points having a numerical value whose value can be found by using a ruler to find difference in the numbers on the ruler that coincides with the points, while

4 0

2 years ago