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shusha [124]
1 year ago
8

If a cube has an edge of 2 feet. The edge is increasing at the rate of 6 feet per minute. How would i express the volume of the

cube as a function of m, the number of minutes elapsed. V(m)= ??
Mathematics
1 answer:
photoshop1234 [79]1 year ago
8 0

Answer:

v(m) = 8 + 48m+ 180m² +216m³

Step-by-step explanation:

Let's first of all represent the edge of the the cube as a function of minutes.

Initially the egde= 2feet

As times elapsed , it increases at the rate of 6 feet per min, that is, for every minute ,there is a 6 feet increase.

Let the the egde be x

X = 2 + 6(m)

Where m represent the minutes elapsed.

So we Al know that the volume of an edge = edge³

but egde = x

V(m) = x³

but x= 2+6(m)

V(m) = (2+6m)³

v(m) = 8 + 48m+ 180m² +216m³

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Answer:

Standard deviation = 8.27 percent

Step-by-step explanation:

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Mathematically,

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x = each variable

xbar = mean = 6 percent

N = number of variables

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σ = √[[(2)² + (-9)² + (6)² + (11)² + (-10)²]/(5)]

σ = √[(4 + 81 + 36 + 121 + 100)/(5)] = √(342/5) = 8.27 percent.

4 0
2 years ago
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d = 49 + 64
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We know that
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