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Greeley [361]
2 years ago
14

Jamal will slice a right circular cylinder into two congruent pieces. Which two dimensional plane sections could result from the

slice Jamal makes?
Mathematics
1 answer:
GarryVolchara [31]2 years ago
5 0

Answer:

An ellipse and a rectangle.

Step-by-step explanation:

If Jamal cuts the right circular cylinder anywhere but its extremities, the resulting shapes on both pieces will be an ellipse.  

If he cuts precisely in a perpendicular way in relation to the ends, he will then form two new right circular cylinders, then the ellipses obtained would be circles.

If Jamal cuts the right circular cylinder lengthwise, going from one end to the other, even if it's not perpendicular to the base, he will obtain a rectangular shape.

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Solve the equation y′ + 3y = t + e^(−2t).
Leni [432]
Hello,

I am going to remember:

y'+3y=0==>y=C*e^(-3t)

y'=C'*e^(-3t)-3C*e^(-3t)

y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9

==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k


4 0
2 years ago
jose is choosing a 3-letter password from the letters a,b,c,d. the password cannot have the same letter repeated in it. how many
kvasek [131]
Alright, so we are dealing with permutations. Permutations are the number of combinations in a specific order possible for the set. 

There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:

_{n}P_{r}= \frac{n!}{(n-r)!}

r= number of elements in the subset

n= number of elements in the set

P= permutations of the set

There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.

Here's the math:

_{n}P_{r}= \frac{n!}{(n-r)!}

_{4}P_{3}= \frac{4!}{(4-3)!}

_{4}P_{3}= \frac{4!}{(1)!}

_{4}P_{3}= \frac{4(3)(2)(1)}{1}

_{4}P_{3}=24

There are 24 permutations. I can prove this by showing you the model:

ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.

Hope this helps!

Answer: 24 passwords are possible
5 0
2 years ago
Jessica purchased a DVD that was on sale for 12% off. The sales tax in her county is 3%. Let y represent the original price of t
Oksi-84 [34.3K]
Y - 12% of y + 3% of y = final cost

may be wrong, havnt done math in a good while
5 0
2 years ago
Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probab
Komok [63]
Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probability that the coach would randomly pick a player over 6 feet tall or a player with a good aim? Assume that no players over 6 feet tall have good aim. A. 7/15 B. 6/15 C. 7/9 D. 5/9

The Answer Is

--------5/9--------
5 0
2 years ago
A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18 \pi18π18, pi
Whitepunk [10]

Answer:

A=81\pi $ m^2

Step-by-step explanation:

Circumference of the column =18\pi $ meters

Circumference of a circle=2\pi r

Therefore:

2\pi r =18\pi $ meters\\2r=18\\r=18 \div 2\\$Radius, r=9 meters

Area of a Circle =\pi r^2

Since radius of the cross section of the column =9 meters

Area of the cross section of the column

=\pi *9^2\\=81\pi $ m^2

5 0
2 years ago
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