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2 years ago

The statement tan theta -12/5, csc theta -13/12, and the terminal point determined by theta is in quadrant 2."

Mathematics

2 answers:

ZanzabumX [31]2 years ago

6 0

Answer is C. This is because in quadrant 2, $\sin\theta>0$ so $\csc\theta>0$ is also true.

IrinaK [193]2 years ago

3 0

Answer with explanation:

Let , Theta =A

$\tan A=\frac{-12}{5}\\\\ \csc A=\frac{-13}{12}$

In First Quadrant all Trigonometric Function are Positive.

→In Quadrant,II , Sine and Cosecant , Function are Positive only.

→Cosecant theta is negative.So, Terminal point can't be in Second Quadrant.

Option C:

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Answer:

Step-by-step explanation:

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2 years ago

Karina read a total of 20 2/4 pages in her science and social studies books combined she read 12 3/4 pages in her science book h

wlad13 [49]

Answer:

8 1/4

Step-by-step explanation:

20 2/4

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8 1/4

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2 years ago

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Answer:

20% of the money was saved from January.

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First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number

Then: divide the increase by the original number and multiply the answer by 100.

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In this context:

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<h2>Explanation:</h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any diagram, so I'll assume ΔSTU and ΔDEF are similar. Two triangles are similar if and only if<em> their corresponding angles are congruent and their corresponding sides are in proportion. </em>

So:

$\angle S=\angle D \ldots eq1 \\ \\ \angle T=\angle E \ldots eq2 \\ \\ \angle U=\angle F \ldots eq3$

We also know:

$\angle S+\angle T+\angle U=180^{\circ} \ldots eq4 \\ \\ \angle D+\angle E+\angle F=180^{\circ} \ldots eq5$

Suppose we know:

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Then, by eq2:

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By substituting ∠S and ∠T into eq4:

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2 years ago

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Answer:

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