The statement tan theta -12/5, csc theta -13/12, and the terminal point determined by theta is in quadrant 2."

Mathematics

2 answers:

ZanzabumX [31]2 years ago

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Answer is C. This is because in quadrant 2, $\sin\theta>0$ so $\csc\theta>0$ is also true.

IrinaK [193]2 years ago

3 0

Answer with explanation:

Let , Theta =A

$\tan A=\frac{-12}{5}\\\\ \csc A=\frac{-13}{12}$

In First Quadrant all Trigonometric Function are Positive.

→In Quadrant,II , Sine and Cosecant , Function are Positive only.

→Cosecant theta is negative.So, Terminal point can't be in Second Quadrant.

Option C:

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