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2 years ago

The statement tan theta -12/5, csc theta -13/12, and the terminal point determined by theta is in quadrant 2."

Mathematics

2 answers:

ZanzabumX [31]2 years ago

6 0

Answer is C. This is because in quadrant 2, $\sin\theta>0$ so $\csc\theta>0$ is also true.

IrinaK [193]2 years ago

3 0

Answer with explanation:

Let , Theta =A

$\tan A=\frac{-12}{5}\\\\ \csc A=\frac{-13}{12}$

In First Quadrant all Trigonometric Function are Positive.

→In Quadrant,II , Sine and Cosecant , Function are Positive only.

→Cosecant theta is negative.So, Terminal point can't be in Second Quadrant.

Option C:

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A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea

uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is $\mu*n$ and the standard deviation is $s = \sqrt{n}*\sigma$

In this question:

$n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250$

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$1.28 = \frac{X - 6328125}{11250}$

$X - 6328125 = 1.28*11250$

$X = 6342525$

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0

1 year ago

The $120 repair bill included $36 for parts and rest for labor. What percent of the bill was for labor?

Bogdan [553]

Answer:

30%

Step-by-step explanation:

3 0

2 years ago

What property describes the number sentence 6+0 = 6

zmey [24]

That is the Identity Property of Addition.
If it is adding and the whole number stays the same it is Identity Property of Addition.
If it is multiplying then it would be the Identity Property of Multipulcation. For example for this problem it would be 6x1 in multipulcation in which the whole number would stay the same.
Here are descriptions of all the properties:
https://wikis.engrade.com/mathproperties1

7 0

2 years ago

Read 2 more answers

. Cara is playing a game. For each dart she can toss onto a board, she

Kaylis [27]

She will need 12 seconds because -20•12=-240

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2 years ago

Two friends race against each other in 100-meter and 800-meter races. Of the 200 races they ran this year, the wins, losses, and

sveta [45]

1. <span>What percentage of all the races are ties?
If</span>The chance for the race become tie is 10% for 100m and 25% for 800m. Assuming that the 200 race is divided equally, then there would be 100 race of 100-m and 100 race of 800-m.
The number of the event of ties would be:
(100*10% + 100*25%)/ 200= 35/200= 17.5%

2. If someone wins the race today, is it more likely for A to win or B to win? How much more likely?The event should be independent because the two events should not influence each other. That means the probability will not change and no one becomes more likely to win the next race.

5 0

2 years ago