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2 years ago

The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function?

Mathematics

1 answer:

Alinara [238K]2 years ago

8 0

Answer:

Locate the ordered pair (0, –6). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points.

Step-by-step explanation:

The answer is the first one because the slope is technically $\frac{2}{1}$

Up 2 over 1

Since the slope is positive, the graph goes to the right.

(0, -6) is the y intercept because it intersects the y - axis.

Then you draw those two points and connect them.

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B) m-5=63 is the answer

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Shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster. The area of the enlarged

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The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.

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The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c

boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

The probability of exactly three flaws in 150 m of cable is

$P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246$

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is $1.2 \cdot 2 =2.4$

$P(X\geq 2)=1-P(X$

$P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155$

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

$P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143$

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

$(0.36143)(0.36143) = 0.13063$

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2 years ago

According to a 2011 report by the United States Department of Labor, civilian Americans spend 2.75 hours per day watching televi

marusya05 [52]

Answer:

Step-by-step explanation:

Confidence interval is written in the form, sample mean ± margin of error

The sample mean is an estimator for the population mean. The confidence level is used to express how confident we are that the population mean is within the calculated confidence interval. The lower limit of the given confidence interval is 2.619 hours/day while the upper limit of the confidence interval is 3.401 hours/day

Therefore, the INVALID interpretations of the 95% confidence interval are

A. About 95% of all Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.

B. There is a 95% chance that, on average, Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.

D. In the long run, 95% of the sample means will be between 2.619 and 3.401 hours.

E. None of the above.

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1 year ago