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Andrej [43]
1 year ago
11

This rectangular frame is made from 5 straight pieces of metal.

Mathematics
1 answer:
Aneli [31]1 year ago
7 0

Answer:

Total weight = 70.5 kg

Step-by-step explanation:

Rectangular frame is made from 5 straight pieces of metal. One of them goes through the diagonal of the rectangle.

2 pieces form the length of the rectangular frame, hence, they have a length of 12 m each

2 pieces from the width of the rectangular frame, hence, they a length of 5 m each

To find the length of the diagonal, we can use Pythagoras Theorem:

Hypotenuse² = Base² + Perpendicular²

Hypotenuse² = 5² + 12²

Hypotenuse² = 169²

Hypotenuse = 13

Hence, the length of the piece of metal placed at the diagonal is 13cm

Find the sum of all lengths of the metal pieces.

Total length = 12 + 12 + 5 + 5 + 13

Total length = 47 m

Total weight = 1.5 × Total length

Total weight = 1.5 kg/m × 47m

Total weight = 70.5 kg

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A financial advisor tells you that you can make your child a millionaire if you just start saving early. You decide to put an eq
Blababa [14]

Answer:

$12159 per year.

Step-by-step explanation:

If I invest $x each year at the simple interest of 7.5%, then the first $x will grow for 35 years, the second $x will grow for 34 years and so on.

So, the total amount that will grow after 35 years by investing $x at the start of each year at the rate of 7.5% simple interest will be given by

x( 1 + \frac{35 \times 7.5}{100}) + x( 1 + \frac{34 \times 7.5}{100}) + x( 1 + \frac{33 \times 7.5}{100}) + ......... + x( 1 + \frac{1 \times 7.5}{100})

= 35x + \frac{x \times 7.5}{100} [35 + 34 + 33 + ......... + 1]

= 35x + \frac{x \times 7.5}{100} [\frac{1}{2} (35) (35 + 1)]

{Since sum of n natural numbers is given by \frac{1}{2} (n)(n + 1)}

= 35x + 47.25x

= 82.25x

Now, given that the final amount will be i million dollars = $1000000

So, 82.25x = 1000000

⇒ x = $12,158. 05 ≈ $12159

Therefore. I have to invest $12159 per year. (Answer)

5 0
1 year ago
Stacey owns a lot that has 180 feet of front footage and contains 36,000 square feet. She purchases two lots adjacent to each si
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The graph of the function f(x)=(x+2)(x+6) is shown

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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the​ plate, including t
vredina [299]

You're looking for the extreme values of x^2+3y^2+13x subject to the constraint x^2+y^2\le1.

The target function has partial derivatives (set equal to 0)

\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2

\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0

so there is only one critical point at \left(-\dfrac{13}2,0\right). But this point does not fall in the region x^2+y^2\le1. There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of x^2+y^2\le1 by

x=\cos u

y=\sin u

with 0\le u. Then t(x,y) can be considered a function of u alone:

t(x,y)=t(\cos u,\sin u)=T(u)

T(u)=\cos^2u+3\sin^2u+13\cos u

T(u)=3+13\cos u-2\cos^2u

T(u) has critical points where T'(u)=0:

T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0

(1)\quad\sin u=0\implies u=0,u=\pi

(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4

but |\cos u|\le1 for all u, so this case yields nothing important.

At these critical points, we have temperatures of

T(0)=14

T(\pi)=-12

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0
1 year ago
If x and y are two positive real numbers such that x 2 +4y 2 =17 and xy =2, then find the value of x- 2y. a. 3 b. 4 c. 8 d. 9
Dafna11 [192]

Answer: The value of x- 2y is a. \pm 3.

Step-by-step explanation:

Given:  x and y are two positive real numbers such that x^2+4y^2=17   and xy= 2 .

Consider (x-2y)^2=x^2-2(x)(2y)+(2y)^2\ \ \ [(a+b)^2=(a^2-2ab+b^2)]

=x^2-4xy+4y^2

=x^2+4y^2-4(xy)

Put  x^2+4y^2=17   and xy= 2 , we get

(x-2y)^2=17-4(2)=17-8=9

\Rightarrow\ (x-2y)^2=9

Taking square root on both sides , we get'

x-2y= \pm3

Hence, the value of x- 2y is a. \pm 3.

7 0
1 year ago
Consider the angle shown below with an initial ray pointing in the 3-o'clock direction that measures θ radians (where 0≤θ&lt;2π)
neonofarm [45]

Answer:

hello attached below is the sketch of the missing diagram

a) h = 2

b) cos^-1 ( 2 ) = ∞

c ) θ ≈ 215°

Step-by-step explanation:

a) The length ( h ) to the right of the circles center

= h^2 = ( -1.15)^2 + ( -1.64)^2

∴ h = 2

b) cos^-1 ( 2 ) = ∞

c) The value gotten from b does not give us the value of θ

AB = - 1.64

BC = -1.15

AC = 2

sin^-1 ( - 1.64 / -1.15 )

cos^1 ( -1.15 / 2 ) gives us the value of θ

tan^-1 ( -1.64 / -1.15 )

∴ θ ≈ 215°

6 0
1 year ago
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