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1 year ago

This rectangular frame is made from 5 straight pieces of metal.

Mathematics

1 answer:

Aneli [31]1 year ago

7 0

Answer:

Total weight = 70.5 kg

Step-by-step explanation:

Rectangular frame is made from 5 straight pieces of metal. One of them goes through the diagonal of the rectangle.

2 pieces form the length of the rectangular frame, hence, they have a length of 12 m each

2 pieces from the width of the rectangular frame, hence, they a length of 5 m each

To find the length of the diagonal, we can use Pythagoras Theorem:

Hypotenuse² = Base² + Perpendicular²

Hypotenuse² = 5² + 12²

Hypotenuse² = 169²

Hypotenuse = 13

Hence, the length of the piece of metal placed at the diagonal is 13cm

Find the sum of all lengths of the metal pieces.

Total length = 12 + 12 + 5 + 5 + 13

Total length = 47 m

Total weight = 1.5 × Total length

Total weight = 1.5 kg/m × 47m

Total weight = 70.5 kg

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Answer:

120*2.75*60/5280

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Step-by-step explanation:

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1 year ago

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Answer:

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2 years ago

Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

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$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

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$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

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Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

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$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

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1 year ago

If the heights of 300 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many studen

Lunna [17]

Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation

Calculate z-scores for the following random variable and determine their probabilities from standard tables.

x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088

x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912

x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587

x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413

Part (a)
For x > 72 in, obtain
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Answer: 27

Part (b)
For x ≤ 64 in, obtain
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Answer: 27

Part (c)
For 65 ≤ x ≤ 71, obtain
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Answer: 204

Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150

Answer: 150

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