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lyudmila [28]
2 years ago
9

The director of marketing at a large company wants to determine if the amount of money spent on internet marketing is a good pre

dictor of company profit. She fits a least-squares regression line to 20 months of data and computes the following regression line:
Profit = 372.6 + 17.2(advertising dollars)

What is the value of the residual for advertising dollars spent equal to $1,020 and Profit equal to $17,500? Round to the nearest integer.
Mathematics
1 answer:
____ [38]2 years ago
6 0
The Answer would be 417 because 416.6 rounded is 417 and to get the answer you take the residual value and the profit into concideratio.
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Victor fue al mercado para comprar manzanas, naranjas y platanos; las naranjas costaron el doble de lo 1ue pago por las manzanas
Thepotemich [5.8K]

Answer:

El precio de las manzanas = 27 pesos

El precio de las naranjas = 54 pesos

El precio de las bananas = 19 pesos

Step-by-step explanation:

Los parámetros dados son;

El monto total gastado = 100 pesos

Sea el precio de las naranjas = x

Sea el precio de las manzanas = y

Sea el precio de los plátanos = z

La cantidad pagada por las naranjas = 2 · y = x

La cantidad pagada por los plátanos = y - 8 = z

Por lo tanto, tenemos;

La cantidad total gastada = La cantidad pagada por las naranjas + La cantidad pagada por las bananas + La cantidad pagada por las manzanas

∴ El monto total gastado = 100 pesos = 2 · y + y - 8 + y

100 = 4 · años - 8

4 · y = 100 + 8 = 108

y = 108/4 = 27

y = 27

De

z = y - 8 tenemos;

z = 27 - 8 = 19

De 2 · y = x, tenemos;

2 × 27 = x

x = 54

Por lo tanto;

El precio de las naranjas = 54 pesos

El precio de las manzanas = 27 pesos

El precio de los plátanos = 19 pesos.

5 0
2 years ago
Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
2 years ago
Read 2 more answers
A man has 28 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 520 cents, how many d
nordsb [41]
Assuming x = dimes, y = quarters

x + y = 28 \\ 0.1x + 0.25y = 5.20

x + y = 28 \\ x = 28 - y

Substitute that into,
0.1(28 - y) + 0.25y = 5.20 \\ 2.8 - 0.1y + 0.25y = 5.20 \\0.15y = 2.4 \\ y = 16

Answer : He has 16 quarters.

Hope this helps. - M
5 0
2 years ago
What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
pentagon [3]

Step-by-step explanation:

1.

2d + 3 \leqslant  - 11 \\ 2d \leqslant  - 11 - 3 \\ 2d \leqslant  - 14 \\  \frac{2d}{2}  \leqslant  \frac{ - 14}{2}  \\ d \leqslant - 7

2.

3d - 9 > 15 \\ 3d > 15 + 9 \\ 3d > 24 \\  \frac{3d}{3}  >  \frac{24}{3}  \\ d = 8

Welcome

3 0
2 years ago
Point b has coordinates (3,-4) and lies on the circle whose equation is x^2 + y^2= 25. If angle is drawn in a standard position
lakkis [162]
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>BO^2=AO^2+AB^2 \\ BO^2=3^2+4^2  \\ BO^2=9+16  \\ BO^2=25  \\ BO=5.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
\sin \angle BOA= \dfrac{AB}{BO} = \dfrac{4}{5} =0.8

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>\sin \theta=-0.8 .





3 0
2 years ago
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