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sergejj [24]
1 year ago
6

Is ½y=1 a linear equation ​

Mathematics
1 answer:
masha68 [24]1 year ago
8 0

Answer:

yes it  

Step-by-step explanation:

1/2y=1

y=1 x 2 (because e do to multiply the one by 2/1 to get y alone)

y=2 ( if y is always equal to two there is no variation meaning it is linear)

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Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

So, remainder is 13 and -13.

5 0
1 year ago
Read 2 more answers
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
2 years ago
Jose rides his bicycle for 5 minutes to travel 8 blocks. He rides for 10 minutes to travel 16 blocks.
kolbaska11 [484]

Answer:

A=8 B=15 C=40

Step-by-step explanation:

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4 0
1 year ago
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Galina-37 [17]
Order does not matter so use "n choose k" formula is used to find number of unique combinations.

c=n!/(k!(n-k)!)  where n is total possible choices and k is number of selections.

c=4!/(2!(4-2)!)

c=4!/(2!2!)

c=24/(2*2)

c=24/4

c=6

So there are 6 different two topping options when there are four different toppings to choose from.
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2 years ago
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Answer:

i promise it's A i am 1,00000000000000000000000000000000000000 sure

Step-by-step explanation:

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2 years ago
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