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almond37 [142]
2 years ago
13

The angle \theta_1θ

Mathematics
1 answer:
enyata [817]2 years ago
8 0

Answer:

sin\theta_1 = \dfrac{\sqrt{217}}{19}

Step-by-step explanation:

It is given that:

cos\theta_1 = -\dfrac{12}{19}

And we have to find the value of sin\theta_1 = ?

As per trigonometric identities, the relation between sin\theta\ and \ cos\theta can represented as:

sin^2\theta + cos^2\theta = 1

Putting \theta_1 in place of \theta Because we are given

sin^2\theta_1 + cos^2\theta_1 = 1

Putting value of cosine:

cos\theta_1 = -\dfrac{12}{19}

sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}

It is given that \theta_1 is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}

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Answer:

B

Step-by-step explanation:

  • Parabola that is opening upward has the form  y=ax^2
  • Parabola opening downward has the form  y=-ax^2
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Where a is a constant

Now, looking at the graph given, it takes the form  x=-ay^2

Where a is 3 (matching the answer).

Hence, B is the correct answer choice.

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2 years ago
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Step-by-step explanation:

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1 year ago
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<h2>Answer:</h2>

The function whose inverse is also a function is:

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<h2>Step-by-step explanation:</h2>

We know that inverse of a function is also a function if it is one-to-one function.

i.e. the graph of the function satisfies the horizontal line test.

i.e. there is a unique image corresponding to each element.

1)

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The function G(x) is a straight increasing line( since the slope is positive)

Hence, the function is 1-1 as it is a strictly increasing function.

Hence, the inverse of G(x) is again a function.

2)

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We know that a quadratic function is never 1-1.

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Hence, the inverse of K(x) is not a function.

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Again we know that the modulus function is not a 1-1 function.

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Answer:

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Step-by-step explanation:

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