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faust18 [17]
2 years ago
14

Juli uses 12 ounces of cheese in her potato soup recipe. Her recipe yields 8 servings. If Juli needs enough for 20 servings, how

many pounds of cheese will she need?
(I’ll mark you Brainleist if you CAN answer it CORRECTLY)

(I promise)
Mathematics
2 answers:
Ludmilka [50]2 years ago
6 0
30 ounces of cheese
ikadub [295]2 years ago
4 0
STEP 1:
Find number of recipes needed for 20 servings (number of times we're multiplying original recipe)
= 20 servings ÷ 8 servings per recipe
= 20/8
= 2 4/8
reduce by 2
= 2 1/2 or 2.5 recipes

STEP 2:
Multiply recipes needed by amount of cheese used per recipe
= 2 1/2 * 12 ounces
convert fraction to improper fraction
= 5/2 * 12
multiply numerators
= (5*12)/2
= 60/2
= 30 ounces of cheese needed

ANSWER: She needs 30 ounces of cheese to make 20 servings.

Hope this helps! :)
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Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

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An object is dropped from a height of 1700 ft above the ground. The function h=-16t^2+1700 gives the object’s height h in feet d
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The answer is
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reasonable domain of h
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8 0
2 years ago
A customer borrowed $2000 and then a further $1000 both repayable in 12 months. What should he have saved if he had taken out on
Neporo4naja [7]

Answer:

a. $60

Step-by-step explanation:  

We will use simple interest formula to solve our given problem.

A=P(1+rt), where

A= Amount after t years.

P= Principal amount.

r= Interest rate in decimal form.      

t= Time in years.

Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.

As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

10\%=\frac{10}{100}=0.10

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A=2000(1+0.10\times 1)

A=2000(1+0.10)

A=2000(1.10)

A=2200

Now let us find amount repayable after 12 months for borrowing $1000.

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A=1000(1+0.10)

A=1000(1.10)

A=1100

Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

\text{Amount repayable for borrowing two separate amounts}=2200+1100=3300

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.

8\%=\frac{8}{100}=0.08

A=3000(1+0.08\times 1)

A=3000(1+0.08)

A=3000(1.08)

A=3240

Now let us find difference between both repayable loan amounts.

\text{Difference between both repayable loan amounts}=3300-3240

\text{Difference between both repayable loan amounts}=60

Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.

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Answer:

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