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charle [14.2K]
2 years ago
12

A town has a population of 19000 and grows at 4% every year. To the nearest year, how long will it be until the population will

reach 43500?
Mathematics
1 answer:
larisa [96]2 years ago
8 0

Answer:

1 year

Step-by-step explanation:

The population can be modelled by the equation:

P=P_0(1 + r)^{t}

From the question, the initial population is

P_0=19000

The annual growth rate is r=0.04

We want to find how long it will take for that population to reach 43500.

We substitute the values to get:

43500=19000(1 + 0.04)^{t}

435=190(1.04)^{t}

\frac{435}{190}  = (1.04)^{t}

t =  \frac{  \ln(2.289) }{1.04}

t = 0.7965

To the nearest year, t= year

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From past experience, a company has found that in carton of transistors: 92% contain no defective transistors 3% contain one def
jasenka [17]

Answer:

E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500

In order to find the variance we need to find first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300

The variance is calculated with this formula:

Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075

And the standard deviation is just the square root of the variance and we got:

Sd(X) = \sqrt{0.3075}= 0.5545

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X

X         0           1           2         3

P(X)    0.92     0.03    0.03     0.02

We can calculate the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500

In order to find the variance we need to find first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300

The variance is calculated with this formula:

Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075

And the standard deviation is just the square root of the variance and we got:

Sd(X) = \sqrt{0.3075}= 0.5545

8 0
2 years ago
What is the factored form of a2 – 121?
Flura [38]

Answer:

The factored form a^2-121 is (a+11)(a-11).

Step-by-step explanation:

Given : a^2-121

We have to write the given expression in factored form.

Factor form of an expression is writing the expression in lower power form such that the product of factors given the original expression

Consider the given expression  a^2-121.

We know the algebraic identity x^2-y^2=(x+y)(x-y)

Here a^2-121=a^2-(11)^2.

Comparing with identity stated above , we have x= a , b = 11 , thus, we get

a^2-(11)^2=(a+11)(a-11).

Thus, the factored form a^2-121 is (a+11)(a-11).

7 0
2 years ago
Kiersten runs a website that helps people learn programming. Every month, Kiersten receives a subscription fee of \$10$10dollar
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1 year ago
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Justifying an Argument Alissa is analyzing an exponential growth function that has been reflected across the y-axis. She states
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The correct answer is C. on edg

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The density of gold is 19.3 g/cm3. A weight of 1 ounce is equivalent to a mass of about 28.35 g. Which of these is closest to th
cluponka [151]

Answer: The side length of the cube is 2.27cm

Step-by-step explanation:

The options are not given, then let's solve this in a general way.

We know that the density of gold is 19.3g/cm^3.

We also know that 1 oz = 28.35g.

And we know the relation:

Density = mass/volume.

Now, let's find the volume of 8 ounces of gold.

First, let's rewrite the density changing the units, from grams to ounces.

We know that:

1 oz = 28.35g

(1 oz/28.35g) = 1.

Then if we multiply the density by this ( that is equal to 1) we can change the units and leave the actual quantity invariant.

d =  19.3g/cm^3 =  19.3g/cm^3*(1 oz/28.35g) = 0.68 oz/cm^3

Now let's use the equation for the density, knowing this time that the mass is 8 ounces.

0.68 oz/cm^3 = mass/volume = 8oz/V

Let's find the value of V

0.68 oz/cm^3 = 8oz/V

V = 8oz/0.68 oz/cm^3 = 11.76 cm^3

Now, we know that this is a cube.

Remember that the volume of a cube of side length L is:

V = L^3

Then we have:

L^3 = 11.76 cm^3

L = ∛11.76 cm^3 = 2.27 cm

The side length of the cube is 2.27cm

8 0
1 year ago
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