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charle [14.2K]
2 years ago
12

A town has a population of 19000 and grows at 4% every year. To the nearest year, how long will it be until the population will

reach 43500?
Mathematics
1 answer:
larisa [96]2 years ago
8 0

Answer:

1 year

Step-by-step explanation:

The population can be modelled by the equation:

P=P_0(1 + r)^{t}

From the question, the initial population is

P_0=19000

The annual growth rate is r=0.04

We want to find how long it will take for that population to reach 43500.

We substitute the values to get:

43500=19000(1 + 0.04)^{t}

435=190(1.04)^{t}

\frac{435}{190}  = (1.04)^{t}

t =  \frac{  \ln(2.289) }{1.04}

t = 0.7965

To the nearest year, t= year

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Vsevolod [243]

Answer: A movie ticket is $9 while a snack is $2

Step-by-step explanation: We shall let a movie ticket be m while a snack is s. So, from the clues given, if two movie tickets and three snacks cost $24, we can write it as the following expression;

2m + 3s = 24

Also if three movie tickets and four snacks cost $35, we can as well write another expression as follows;

3m + 4s = 35.

Now we have a pair of simultaneous equations which are

2m + 3s = 24 ----------(1)

3m + 4s = 35 ----------(2)

We shall solve this by using the elimination method, since none of the variables has a coefficient of 1. We'll start by multiplying equation (1) by 3 and multiplying equation (2) by 2 (so as to eliminate the m variable)

2m + 3s = 24 -------- x3

3m + 4s = 35 ---------x2

We now arrive at the following

6m + 9s = 72--------(3)

6m + 8s = 70--------(4)

Subtract equation (4) from equation (3) and we arrive at

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Having determined that s equals 2 we can now substitute for the value of a into equation (1)

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2m + 3(2) = 24

2m + 6 = 24

Subtract 6 from both sides of the equation

2m + 6 - 6 = 24 - 6

2m = 18

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Therefore one movie ticket costs $9 while one snack costs $2

6 0
2 years ago
Suppose abby tracks her travel time to work for 60 days and determines that her mean travel time, in minutes, is 35.6. assume th
HACTEHA [7]
Given that:
mean,μ=35.6 min
std deviation,σ=10.3 min
we are required to find the value of x such that 22.96% of the 60 days have a travel time that is at least x.
using z-table, the z-score that will give us 0.2296 is:-1.99
therefore:
z-score is given by:
(x-μ)/σ
hence:
-1.99=(x-35.6)/10.3
-20.497=x-35.6
x=35.6-20.497
x=15.103


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