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Hitman42 [59]
2 years ago
5

The statements below can be used to prove that the triangles are similar. ? △ABC ~ △XYZ by the SSS similarity theorem. Which mat

hematical statement is missing? ∠B ≅ ∠Y ∠B ≅ ∠Z

Mathematics
2 answers:
Vsevolod [243]2 years ago
8 0

Solution:

It is given that two triangles Δ ABC and Δ X Y Z are similar by Side -Side - Side(SSS)  Similarity theorem.

So, the Statement which is given, that is →→∠B ≅ ∠Y and ∠B ≅ ∠Z, is inadequate for similarity criterion by SSS, as these statement are about angles of Triangles,not sides, which can't be true.

So, if the two triangles are Similar by SSS criterion , then the appropriate mathematical statement must be,

⇒\frac{AB}{XY}=\frac{BC}{ZY}=\frac{AC}{XZ}

wel2 years ago
8 0

Answer:

I think it i s the third option.

Step-by-step explanation:

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To make lemonade, you used one quart of water, one pint of lemon juice, and 9 ounces of your secret ingredient: honey. How much
WITCHER [35]
To solve this problem you must follow the proccedure shown below:

 1. Amount of lemonade in pints:

 1 <span>quart of water=2 pints
 1 pint of lemon
 (9  ounces of honey)(0.0625 pints/1 ounce)=0.56 pints

 Total in pints=2 pints+1 pint+0.56 pints
 Total in pints=3.56 pints

 2. </span>Amount of lemonade in<span> cups:

 Total in cups=(3.56 pints)(2 cups/1 pint)
 Total in cups=7.12 cups

 
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4 0
2 years ago
Jar A contains four liters of a solution that is 45% acid. Jar B contains five liters of a solution that is 48% acid. Jar C cont
castortr0y [4]

Answer:

k= 80%

Step-by-step explanation:

Jar A contains 4*0.45 L acid, and 4 L of a solution  of acid.

Jar B contains 5*0.48 L acid., and 5 L of a solution of acid.

Jar C contains 1*k/100 = k/100 acid, and 1 L of a solution.

50% = 0.5

For jar A.

(2/3)*k/100 L acid  is added to jar A.

Now jar A contains   4*0.45 L + (2/3)*k/100 L acid, and it has (4+2/3)L of a solution.

L solute/L solution = 0.5

[4*0.45 L + (2/3)*k/100 L]/(4+2/3)L = 0.5

[1.8 + (2k/300)]/[(12+2)/3] = 0.5

[1.8 + (2k/300)]/[14/3] = 0.5

[1.8 + (2k/300)]= 0.5*(14/3)

(2k/300) = 0.5*(14/3) - 1.8

2k = (0.5*(14/3) - 1.8)*300

k = (0.5*(14/3) - 1.8)*300/2 =80

k= 80%

We also can find k using jar B.

(1/3)k/100 L acid is added  to jar B.

Now jar B contains 5*0.48 L+ (1/3)k/100 L acid, and it has (5+1/3) L of a solution.

L solute/L solution = 0.5

[5*0.48 L+ (1/3)k/100 L ]/(5+1/3)L= 0.5

[5*0.48 + (1/3)k/100 ]/(5+1/3)= 0.5

This equation also gives k=80%

Check.

We can check at least for jar A.

Jar A has 4L solution and 4*0.45=1.8 L acid.

2/3 L of the solution from jar C was added, and now we have 4 2/3 L of solution.

(2/3)* 80%= (2/3)*0.8 acid was added from jar C.

Now we have [1.8 +(2/3)*0.8] L acid in jar A.

L solute/L solution =  [1.8 +(2/3)*0.8] L /(4 2/3) L = 0.5 or 50%  as it is given that jar A has 50% at the end.

7 0
2 years ago
Choose the function whose graph is given by:
katen-ka-za [31]

Answer:

D. y=\tan (x-\pi)+2

Step-by-step explanation:

We are given the graph of the transformed tangent function.

As, we can see that the graph is shifted 2 units upwards.

That is, the parent function is translated 2 units up.

So, the new function will be of the form, y=\tan (x)+2.

Thus, options A and C are not correct.

Moreover, 'If a function f(x) has period P, then the function cf(bx) will have period \frac{P}{|b|}.

Also, form the figure, we see that the period of the graphed function is \pi.

Since, y=\tan (x) have period \pi.

So, function in option B will have period \frac{\pi}{2}, which is not possible.

<em>Further, function in option D have period \pi.</em>

Thus, the equation of the graphed function is, y=\tan (x-\pi)+2.

7 0
2 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

In the field of statistics, the population of interest may be defined as the group or the population from which the experimenter or the researcher tries to make conclusions or draw their results.

In the context, I am interested to study the cost of the rented house that is more than others in the West Campus area.

So I recorded the monthly rents of the apartments from a sample of 30 one bedroom apartments.

Therefore, the population of interest for my study here is the monthly rents recorded from the sample of one bedroom apartments.

5 0
2 years ago
The 40th term of the number sequence is 119.<br> (b) Work out the 41st term of the number sequence.
dolphi86 [110]
100000fjwjsnfbc kdjdbf
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2 years ago
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