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seraphim [82]
2 years ago
12

The box plots compare the number of students in Mr. Ishimoto’s classes and in Ms. Castillo’s classes over the last two semesters

.
Which statement is true about the box plots? Check all that apply.
-Both box plots show the same range.
-Both box plots show the same interquartile range.
-The data for Mr. Ishimoto has an outlier.
-Mr. Ishimoto had the class with the greatest number of students.
-The smallest class size was 24 students.

Mathematics
2 answers:
Ilya [14]2 years ago
7 0
<span>-Both box plots show the same interquartile range.
 >Interquartile range (IQR) is computed by Q3-Q1. 
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.

</span><span>-Mr. Ishimoto had the class with the greatest number of students.
 >Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.

</span><span>-The smallest class size was 24 students.
 >Which was Ms. Castillo's class.</span>
lorasvet [3.4K]2 years ago
6 0

Answer:

Step-by-step explanation:

In case of Mr. Ishimoto's class

Minimum :

Q_0 = 28

Lower Quartile :

Q_1 = 31

Median :

Q_2 = 33

Upper Quartile

Q_3 = 35

Maximum :

Q_4 = 40

In Case of Ms. Castilllo's class

Minimum :

Q_0 = 24

Lower Quartile :

Q_1 = 30

Median :

Q_2 = 31

Upper Quartile

Q_3 = 34

Maximum :

Q_4 = 38

Now range : Q_4 - Q_0

Range of Mr. Ishimoto's class : 40-28 =12

Range of Ms. Castilllo's class: 38-24 =14

Thus option A is incorrect since the range of the both box plots are not same

Inter quartile range :  Q_3 - Q_1

Inter quartile range(IQR) of Mr. Ishimoto's class : 35-31=4

Inter quartile range (IQR)of Ms. Castilllo's class: 34-30=4

Thus Option B is correct : Both box plots show the same interquartile range.

Now for the outlier of Mr. Ishimoto's class:

Q_1 - 1.5*IQR

31-1.5*4

31-6

25

Q_3+1.5*IQR

35+1.5*4

35+6

41

Thus the interval for outlier is(25,41)

Since all the values of the box plot lies within this interval .

So,The data for Mr. Ishimoto has no outlier.

Thus Option C is incorrect.

Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.

So, Mr. Ishimoto's class  have greatest number of students.

Thus option D is correct.

The smallest class size was 24 students.

Which was Ms. Castillo's class.

So, Option E is true for Ms. Castillo's class.

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Answer:

P1 bribe P3 otherwise P3 gets 100 gold coins.

Step-by-step explanation:

Under this rule

P1 gets 34 coins,

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Two things could happen

First: P1 has to bribe P3 additional one gold coin in order to get majority votes, so that he would not be thrown overboard and be kill. Then,

P1 gets 33 coins

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Second: if P2 reject it, P3 could be indifferent. This will lead to the death of P1. And when P2 makes suggestions, P3 rejects it. Therefore P3 gets it all. P3 gets 100 gold coin

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Louisa biked 50 4/5 miles in 4 hours. How many miles did she bike per hour?
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Divide 50 4/5 by 4
254/5
divide the top by 4
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2 years ago
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I think it's 1:40 (g) (^^)
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A video game randomly chooses your car color and type. The probability of getting a red car is 0.20, and the probability of gett
pishuonlain [190]

Answer: Option 'D' is correct.

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Since we have given that

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and

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Similarly,

Event B: You get a convertible

and

P(B)=0.40

So, if A and B are independent , then they must satisfy,

P(A).P(B)=P(A\cap B)

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7 0
2 years ago
Trevor’s total employment compensation is $33,500. If Trevor has no job expenses and his gross pay is $28,600, then his total em
Paraphin [41]

we know that

Total\  employment\  compensation=gross\  pay+employee\  benefits-job\  expenses

in this problem

Total\  employment\  compensation=33,500\ dollars

gross\  pay=28,600\ dollars

job\  expenses=0

Step 1

Find the total employee benefits

Let

EC------> total employment compensation

EB--------> total employee benefits

GP------> gross pay

JE------> job expenses

EC=GP+EB-JE

33,500=28,600+EB-0\\ EB=33,500-28,600\\ EB=4,900\ dollars

Step 2

Find the percentage of the total employee benefits

we know that

total employee benefits is equal to 4,900\ dollars

gross pay is equal to 28,600\ dollars

by proportion

\frac{28,600}{4,900} =\frac{100}{x} \\ \\ x*28,600=100*4,900\\ \\ x=\frac{100*4,900}{28,600}

x=17.1%

therefore

the answer is the option

d. 17.1


5 0
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