The answer to the question
There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the
1 answer:
Answer:
Probability that the result is a multiple of 4 or a multiple of 3= 0.428
Step-by-step explanation:
The spinner is divided into 14 equal areas.
Probability of an event=
For favourable events,result should be a multiple of 3 or 4.
All the possible outcomes are=1,2,3,4,5,6,7,8,9,10,11,12,13,14
- Multiples of 3=3,6,9,12
- Multiples of 4=4,8,12
Hence the favourable outcomes are=3,4,6,8,9,12
Number of favourable outcomes=6
Total number of outcomes=14
Probability=
=0.428
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Answer:
The constraints are
and
Step-by-step explanation:
Let
x ----> represent the number of male birds
y ----> represent the number of female birds
we know that
The flock needs to have exactly three times more females than males to thrive
so
----> equation A
The zoo only has room for a maximum of 20 male birds
so
----> inequality B
we know that
The maximum number of male birds is 20
For x=20
substitute in the equation A
so
The maximum number of female birds is 60
so
----> inequality C
therefore
The constraints are
and
Answer:
4
Step-by-step explanation:
Here let the number of ride tickets be r, and the number of food tickets be f.
Hence
We first plot the two inequalities on graph as shown in attachment. From the graph we see that the two in-equation meet at (4,12)
Hence we can see that the maximum value of r is 4
Answer:
Option 3 is correct.
The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games.
Step-by-step explanation:
Before anything else, we first give the null and alternative hypothesis for this question.
Null hypothesis would be that there isn't significant evidence to conclude that the mean point spread of home games is higher than that of away games.
H0: µ1 = µ2
And the alternative hypothesis would be that there is significant evidence to conclude that the mean point spread of home games is higher than that of away games.
Ha: μ1 > μ2
The data from the output of the analysis of the hypothesis test is missing from the question. It was obtained online and is attached to this solution of the question.
The table consists of the difference, the sample mean, the standard error of the mean, degree of freedom, the test statistic and most importantly, the p-value. It is the p-value that absolutely gives us the concluding statement of the hypothesis testing.
When the significance level for a test isn't provided, the convention is usually to use 5% significance.
Interpretation of p-value
When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.
So, for this question, significance level = 0.05
p-value = 0.4351
0.4351 > 0.05
Hence,
p-value > significance level
This means that we fail to reject the null hypothesis & say that 'The data do not provide sufficient evidence to reject H0; thus, we cannot conclude that the mean point spread of home games is higher than that of away games'.
Hope this Helps!!!
