Nathan wants to buy a car that costs $25,920 he has $3,000 as a down payment and his payments will be $450 for 6 years through r
1 answer:
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Answer:
The 95% confidence interval for the average price of a home in Gainesville of this size is between 183,772.5 square feet and 242,207.5 square feet.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the students t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 6 - 1 = 5
Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 0.95(). So we have T = 2.015
The margin of error is:
M = T*s = 2.015*14500 = 29217.5.
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 212990 - 29217.5 = 183,772.5 square feet
The upper end of the interval is the sample mean added to M. So it is 212990 + 29217.5 = 242,207.5 square feet
The 95% confidence interval for the average price of a home in Gainesville of this size is between 183,772.5 square feet and 242,207.5 square feet.
Answer:
(a) 0.7967
(b) 0.6826
(c) 0.3707
(d) 0.9525
(e) 0.1587
Step-by-step explanation:
The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and variance <em>σ</em>² = 36.
(a)
Compute the value of P (X > 5) as follows:
Thus, the value of P (X > 5) is 0.7967.
(b)
Compute the value of P (4 < X < 16) as follows:
Thus, the value of P (4 < X < 16) is 0.6826.
(c)
Compute the value of P (X < 8) as follows:
Thus, the value of P (X < 8) is 0.3707.
(d)
Compute the value of P (X < 20) as follows:
Thus, the value of P (X < 20) is 0.9525.
(e)
Compute the value of P (X > 16) as follows:
Thus, the value of P (X > 16) is 0.1587.
**Use a <em>z</em>-table for the probabilities.
Answer:
The correct option is
Step-by-step explanation:
The parameters given are;
The length of the string = 10 inches
The speed or rate of travel of the wave = c inches per millisecond
The position on the string from the left-most end = x
The time duration of motion of the vibration to reach x= 0.3 milliseconds
The distance covered = Speed × Time = c×0.3
Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;
The location on the string where it is plucked = center of the string = 10/2 = 5 inches
Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches
Therefore, on the left side of the center of the string we have;
The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)
On the right side of the center, the distance from x is -(5 - x) = x - 5
Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is or
which gives the correct option as A